How did they get kg at the end please help mi u mass oidlan g iceHeat Transfer rate due to conduetivity,dQdtdQ is change in energydt b timeKA AT%3DdQ- m;(bdtk = 0.033 W/mkAT is temperature dfferencek io conductivity og styrfoomA i surface ariat u thikness.%3DThr = 3600 seconds4 is ladent heat of fusion of icemi n mass oficdmelted.A =0.016 mAT = 35 - 0 = 35t = 2x10-mL=33600 J/KStep2b)= KA AT dt0.033 X0.0l6 X 35 X 360 02x10-3 x 336 00mimi - 0.99 kgmow ofmassice melted .

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Answered: Step2 b) .*. mi = KA AT dt 0.033 XO.016…

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Step2 b) .*. mi = KA AT dt 0.033 XO.016 X 35 X 360 0 2x10-3 x 336 00 こ mi - 0.99 kg mass of ice melted .

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter1: Temperature And Heat

Section: Chapter Questions

Problem 97P: Compare the rate of heat conduction through a 13.0-cm-thick wall that has an area of 10.0 m2 and a...

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