Step The complete factorization of the second term along with the properties of exponents will allow us to write the second term as a perfect cube. We know that 6 ÷ 3 = so x6 = (x2)3. Express each term as a perfect cube. 27d³64 33d³ - 26 3³d³- = (3d) ³ - (1 ])²)³ 1²
Step The complete factorization of the second term along with the properties of exponents will allow us to write the second term as a perfect cube. We know that 6 ÷ 3 = so x6 = (x2)3. Express each term as a perfect cube. 27d³64 33d³ - 26 3³d³- = (3d) ³ - (1 ])²)³ 1²
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.2: Exponents And Radicals
Problem 83E
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![Step 2
The complete factorization of the second term along with the properties of exponents will allow us to write the second
term as a perfect cube. We know that 6 + 3 =
so x6 =
(x²)3.
Express each term as a perfect cube.
27d³ - 64 = 3³d326
3³d³-((
=
¤ (3d)³ –
=
1²) ³
1)³](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22926f56-41bb-43d5-b1fa-42be8a3ae12e%2F5797ca73-5531-4568-8370-fd9b67e32f65%2F6uwlsrv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Step 2
The complete factorization of the second term along with the properties of exponents will allow us to write the second
term as a perfect cube. We know that 6 + 3 =
so x6 =
(x²)3.
Express each term as a perfect cube.
27d³ - 64 = 3³d326
3³d³-((
=
¤ (3d)³ –
=
1²) ³
1)³
![Express each term as a perfect square.
49b² - 64 =
])²-(²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F22926f56-41bb-43d5-b1fa-42be8a3ae12e%2F5797ca73-5531-4568-8370-fd9b67e32f65%2F0ohmaui_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Express each term as a perfect square.
49b² - 64 =
])²-(²
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