Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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Question
Step 2 The complete factorization of the second term along with the properties of exponents will allow us to write the second term as a perfect cube. We know that 6 + 3 = so x6 = (x²)3. Express each term as a perfect cube. 27d³ - 64 = 3³d326 3³d³-(( = ¤ (3d)³ – = 1²) ³ 1)³
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Transcribed Image Text:Step 2 The complete factorization of the second term along with the properties of exponents will allow us to write the second term as a perfect cube. We know that 6 + 3 = so x6 = (x²)3. Express each term as a perfect cube. 27d³ - 64 = 3³d326 3³d³-(( = ¤ (3d)³ – = 1²) ³ 1)³
Express each term as a perfect square. 49b² - 64 = ])²-(²
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Transcribed Image Text:Express each term as a perfect square. 49b² - 64 = ])²-(²
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