Step 3 The integral 27 12xe dx can be done with the substitution u = 2 and du %3D -2x dx. -2.r Step 4 With the substitution, we have 2n | 12xe-x dx = - 127 eu du 127 12ne + C. 12me" Step 5 Going back to x, the volume of our solid is = 144
Step 3 The integral 27 12xe dx can be done with the substitution u = 2 and du %3D -2x dx. -2.r Step 4 With the substitution, we have 2n | 12xe-x dx = - 127 eu du 127 12ne + C. 12me" Step 5 Going back to x, the volume of our solid is = 144
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve step 5 only
Transcribed Image Text:Step 3
The integral 2n
12xex
dy can be done with the substitution u =-x
and du
|-2x
dx.
-2.r
Step 4
| 12xex dx = - 127
With the substitution, we have 2n
eu du
127
|12ле
+ C.
12ze"
Step 5
Going back to x, the volume of our solid is
144
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