Step 1: Solve for the reactions at support A A H 19 18 IC 10 E Im 2m 2m 1m + Y ¥ Av 10 KN D KN 10kW Ev 1m 2m LEFT SECTION 616 SOLVE FOR REACTION AT SUPPORT IM₂ = 0 C+ Av (6) 10 (5)-10 (3)-10 (1)-0 ZFV = 0 ↑+ IS-10-10-10 + EV-0 Ev = 15 KN Step 2: Cut a section into a truss where the required forces are Note: You can only cut three members when using method of section. We have to first determine the slopes of GH and BG which are for GH is 2H:1V and for BG is 2H:3V. HS 2 Im BG √√13 2m 2 Анод BC B 2m- Av=15kW 10KW 9 Step 3: Solve for the forces required, BC,BG and GH *To determine BC we take summation of moment forces along G so that the other two unknowns BG and GH will be canceled G because their paths go to point

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small terms (H.W.); 1b = 14T-1 + + ... 9.29a. 27₁ 1 = ns [1-, ²-₁ (47) (1-²)] ... 6.29b. Since T₁ >> AT, then: nblade = ns ... 6.30a. If the degree of reaction is not 50%, then; 1 ns=(nrotor + nstator) .6.30b. Or, more accurately: ns = Anrotor + (1 - A)nstator ... 6.30c. Compressor stage efficiency which governs the final pressure ratio, is dependent on the losses for each of the blade rows comprising the stage. Blades row friction loss must be measured in cascade tests. ***

verifyy the Answer R_B=562lb and M_B =2324lb-in. (Show all the work within 20-30mins)