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Step 1 : Show that the voltage division rule for two capacitors in series as in the figure Step 2: For two capacitors in parallel as in the second figure, show that the current division rule is:

Step 1 : Show that the voltage division rule for two capacitors in series as in the figure Step 2: For two capacitors in parallel as in the second figure, show that the current division rule is:

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Step 1 : Show that the voltage division rule for two capacitors in series as in the figure Step 2: For two capacitors in parallel as in the second figure, show that the current division rule is:
HD INDUCTORES Y CAPACITORES UNIDAD 3: ANÁLISIS DE CIRCUITOS EN CORRIENTE ALTERNA Demuestre que la regla de la división de tensión para dos capacitores en serie como en la figura 6.59a) es Us. V₂ = C₁ C₂ C₁ V₂ C₁ + C₂ suponiendo que las condiciones iniciales son de cero. C₁ V₁ == a) 0₂ C₂ 4 (1) +4 b) C₁ ¹2 C₂ En relación con dos capacitores en paralelo como en la figura 6.59b), demuestre que la regla de la división de corriente es G+C₂ 2=G₁+6₂² C₁ + C₂ suponiendo que las condiciones iniciales son de cero.
Transcribed Image Text:HD INDUCTORES Y CAPACITORES UNIDAD 3: ANÁLISIS DE CIRCUITOS EN CORRIENTE ALTERNA Demuestre que la regla de la división de tensión para dos capacitores en serie como en la figura 6.59a) es Us. V₂ = C₁ C₂ C₁ V₂ C₁ + C₂ suponiendo que las condiciones iniciales son de cero. C₁ V₁ == a) 0₂ C₂ 4 (1) +4 b) C₁ ¹2 C₂ En relación con dos capacitores en paralelo como en la figura 6.59b), demuestre que la regla de la división de corriente es G+C₂ 2=G₁+6₂² C₁ + C₂ suponiendo que las condiciones iniciales son de cero.
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