Suppose the mean starting salary for nurses is $66,613 nationally. The standard deviation is approximately $10,638. The starting salary is not normally distributed but it is mound shaped. A sample of 41 starting salaries for nurses is taken. State the random variable. Starting salary for a nurse. The mean starting salary of a nurse. The standard deviation of starting salaries of nurses. What is the mean of the distribution of all sample means? Hg = What is the standard deviation of the distribution of all sample means? Round to five decimal places. Og = What is the shape of the sampling distribution of the sample mean? Why? You can say the sampling distribution of the sample mean is not normally distributed since the sample size is greater than 30. You can say the sampling distribution of the sample mean is normally distributed since the sample size is greater than 30. You can't say anything about the sampling distribution of the sample mean, since the population of the random variable is not normally distributed and the sample size is greater than 30. Find the probability that the sample mean is less than $68,341. Round to four decimal places. P(8 < 68341) = Find the probability that the sample mean is less than $59,851. Round to four decimal places. P(x < 59851)= If you did find a sample mean of MORE THAN $68,341 would you find that unusual? What could you conclude? It is not unusual to find a sample mean more than $68,341, since the probability is at least 5%. If you find a sample mean more than $68,341, then it may indicate that the population mean has not changed. It is unusual to find a sample mean more than $68,341, since the probability is less than 5%. If you find a sample mean more than $68,341, then it may indicate that the population mean has changed. It is unusual to find a sample mean more than $68,341, since the probability is at least 5%. If you find a sample mean more than $68,341, then it may indicate that the population mean has changed. It is not unusual to find a sample mean more than $68,341, since the probability is less than 5%. If you find a sample mean more than $68,341, then it may indicate that the population mean has not changed.

A population has a mean p= 79 and a standard deviation o = 12. Find the mean and standard deviation of a sampling distribution of sample means with sample size n = 36. %3D H=(Simplify your answer.) %3D (Simplify your answer)

Use the normal distribution of SAT critical reading scores for which the mean is 514 and the standard deviation is 115. Assume the variable x is normally distributed. (a) What percent of the SAT verbal scores are less than 650​? (b) If 1000 SAT verbal scores are randomly​ selected, about how many would you expect to be greater than 550​? Click to view page 1 of the standard normal table. LOADING... Click to view page 2 of the standard normal table. LOADING...       Question content area bottom Part 1 (a) Approximately 1.181.18​% of the SAT verbal scores are less than 650. ​(Round to two decimal places as​ needed.) Part 2 (b) You would expect that approximately 0.880.88 SAT verbal scores would be greater than 550. ​(Round to the nearest whole number as​ needed.)

Find the standard deviation for the given sample data. Round your answer to one more decimal place than is present in the original data. Listed below are the amounts of weight change (in pounds) for 12 women during their first year of work after graduating from college. Positive values correspond to women who gained weight and negative values correspond to women who lost weight. 15  -5  14  8  -1  10  -6  1  0  4  -3  9

You would like to know the average hourly wage in your area. You ask 20 people, and find a sample mean of 8.50 dollars. The population standard deviation is 2.89 dollars. Assume that distribution is normal. a. Give a point estimate for the mean hourly wage.b. Give the 90% margin of error for the mean. c. Write a sentence about the results. The average hourly wage in my area is about ________, give or take _______.

A population has a mean p= 75 and a standard deviation o= 6. Find the mean and standard deviation of a sampling distribution of sample means with sample size n= 36. (Simplify your answer.)

Find the range, the standard deviation, and the variance for the given sample. Round non-integer results to the nearest tenth. 3, 4, 4, 5, 5, 6, 15 range       standard deviation       variance

The range is (Simplify your answer.) The population mean is (Simplify your answer. Round to the nearest tenth as needed.) The population variance is (Simplify your answer. Round to the nearest tenth as needed.) The population standard deviation is (Simplify your answer. Round to the nearest tenth as needed.)

Find the variance and the standard deviation (correct to two decimal places). 78, 89, 94, 94, 95 variance standard deviation