The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days. a. In a letter to an advice column, a wife claimed to have given birth 309 days after a brief visit from her husband, who was working in another country. Find the probability of a pregnancy lasting 309 days or longer. What does the result suggest? b. If the length of pregnancy is in the lowest 4%, then the baby is premature. Find the length that separates premature babies from those who are not considered premature. a. The probability that a pregnancy will last 309 days or longer is (Round to four decimal places as needed.)

The mean of a normal probability distribution is 600; the standard deviation is 20. About 95% of the observations lie between what two values?

In the 1992 presidential election, Alaska's 40 election districts averaged 2118 votes per district for President Clinton. The standard deviation was 577. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.1. Find the probability that a randomly selected district had between 2236 and 2434 votes for President Clinton. 2. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.

What type of distribution is this : you measure the GPA of every student in a high school to the nearest thousandth?

According to a study done by De Anza students, the height for Asian adult males is normally distributed with an average of 66 inches and a standard deviation of 2.5 inches. Suppose one Asian adult male is randomly chosen. Let X = height of the individual. Find the probability that the person is between 64 and 69 inches. The middle 40% of heights fall between what two values?Write the probability statement. State the two values. (Round your answers to one decimal place.) x1,x2   ch6#9

In the 1992 presidential election, Alaska's 40 election districts averaged 2008 votes per district for President Clinton. The standard deviation was 573. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. Find the probability that a randomly selected district had fewer than 2096 votes for President Clinton. b. Find the probability that a randomly selected district had between 2047 and 2177 votes for President Clinton.c. Find the third quartile for votes for President Clinton. Round your answer to the nearest whole number.

The Greenville Power Authority states that the mean monthly energy bill for their customers is $228 with a standard deviation of $38. They know that energy bills follow a normal distribution. a. Between what two values do we expect 99.7% of energy bill’s to fall? b. What is the probability of a randomly selected energy bill at least $190?

Cody took his first physics exam and scored an 80. The population mean for this exam is 70, and the standard deviation is 5. What is the probability of selecting a person with a score greater than Cody’s?

According to National Testing data, college math class testing times are normally distributed with a mean of 54 minutes and standard deviation 7 minutes. The bell curve below represents the probability distribution for testing times. The scale on the horizontal axis is equal to the standard deviation. Fill in the three indicated boxes. l = 54 o = 7

The NJ Department of Health has reported the average life span of NJ residents is 81 years. If the standard deviation is σ = 4 years, what is the probability of a person living to at least 92 years of age?