State which type of parameter is to be estimated, and the correct method for the following. Do not solve Part: 0/3 Part of 3 (a) A simple random sample of size 48 has mean overline x = 3.1. The population standard deviation is a = 1 62 Construct a 99% confidence interval for the population mean The parameter is the population (Choose one) The correct method to find the confidence interval is the (Choose one )method.

Complete parts a through d

n1=16 x‾1=124 s1=35   n2=12 x‾2=86 s2=31 Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are not equal and that the two populations are normally distributed. Copy Data Step 2 of 3 :   Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places. Step 3 of 3 : Please also find the high and low endpoints and round to four decimal points.

You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 70 dates, the mean record high daily temperature in a certain city has a mean of 86.37°F Assume the population standard deviation is 14.38 F The 90% confidence interval is ( I) (Round to two decimal places as needed.) The 95% confidence interval is ( D (Round to two decimal places as needed.) Which interval is wider? Choose the correct answer below. The 90% confidence interval The 95% confidence interval Interpret the results. O A. You can be 90% confident that the population mean record high temperature is between the bounds of the 90% confidence interval, and 95% confident for the G50% intonial Click to select your answer(S). 180min ZoT oo