Starting with an initial speed of 5.38 m/s at a height of 0.380 m, a 1.87-kg ball swings downward and strikes a 5.13-kg ball that is at rest, as the drawing shows. (a) Using the principle of conservation of mechanical energy, find the speed of the 1.87-kg ball just before impact. This value is 6.03 m/s (b) Assuming that the collision is elastic, find the velocity (magnitude and direction) of the 1.87-kg ball just after the collision. This value is -2.01 m/s (c) Assuming that the collision is elastic, find the velocity (magnitude and direction) of the 5.13-kg ball just after the collision. This value is 3.22 m/s
Starting with an initial speed of 5.38 m/s at a height of 0.380 m, a 1.87-kg ball swings downward and strikes a 5.13-kg ball that is at rest, as the drawing shows.
(a) Using the principle of conservation of mechanical energy, find the speed of the 1.87-kg ball just before impact.
This value is 6.03 m/s
(b) Assuming that the collision is elastic, find the velocity (magnitude and direction) of the 1.87-kg ball just after the collision.
This value is -2.01 m/s
(c) Assuming that the collision is elastic, find the velocity (magnitude and direction) of the 5.13-kg ball just after the collision.
This value is 3.22 m/s
(d) How high does the 1.87-kg ball swing after the collision, ignoring air resistance? (e) How high does the 5.13-kg ball swing after the collision, ignoring air resistance?
I just need d and e answered please! Thank you.
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