Standardization of a Solution A 50.00 mL aliquot portion of 0.01020 M KIO3 solution was transferred into a conical flask. After adding 2.0 g KI and 2 mL of 6M HCl, the mixture was titrated with 31.32 mL of the Na2S2O3 solution to the starch end point. Calculate the number of mmoles of IO3-. mmoles 103- How many mmoles of 12 was released after the addition of KI? mmoles I: How many mmoles Na2S2O3 reacted with the Iz produced? mmoles Na2S₂O3- What is the molarity of the Na2S2O3 solution? M Na2S2O3 Write the half reaction representing the transformation of OC1- (hypochlorite ion) to Cl-(chloride) in acidic medium. Reduction Half Reaction: Write the half reaction representing the transformation of 1- (iodide ion) to I2 (iodine) in acidic medium. Reduction Half Reaction: Analysis of Household Bleaching Agent The composition of a commercially available household bleaching agent is advertised as 5% (w/v) NaOC1. Calculate the number of mmoles of NaOCI present in 50 mL of the bleaching agent. mmol . Calculate the number of mmoles of Na2S2O3 that will react with the 12 that is generated from the reactions of the KI with the NaOCI present in 50-mL of the bleaching agent. mmol Na2S₂O3 How many mL of 0.1025 M Na2S2O3 are required to deliver this amount? mL

Solute, A, has a distribution ratio between water and ether of 7.5 A 50 ml aqueous solution of 1M of compound A was extracted with two consecutive extraction of 25ml ether( 25 x2); calculate the percent of A remaining in the aqueous phase Select one: 21.1 % 1.6 % 4.4 % 11.7 % 1.38 %

1)A bottle of concentrated aqueous sulfuric acid, labeled 95.00 wt% H2SO4, has a concentration of 16.5 M. Calculate the density of 95.00 wt% H2SO4.  2)Ascorbic acid in 5 vitamin C tablets was measured by a titration against (100 ± 0.002 M) NaOH solution. It required 10.00 ± 0.05 mL NaOH solution to reach the equivalent point. What is the average quantity of ascorbic acid per vitamin tablet?

To 47.62 ml of wine were added 5 mL of concentrated KI solution and 32.11 mL of solution containing (0.7557 g KIO 3)/(100.00 mL solution). The wine+reagent mixture was acidified with 10 ml of 1 M HCI to create a known number of moles of I 2 by the reaction 10 3 + excessl + some H*-> 31 2 Some of this I 2 immediately reacted with the sulfite in the wine sample by the reaction SO 3 +12 --> products we don't care about The left over I 2 was titrated to a starch end point with 10.14 mL of 0.04521 M thiosulfate solution, by the reaction 12+ 25 20 32-> products we don't care about What is the concentration of sulfite in the wine, expressed in mM?

2. What is the molarity of a stock solution that is 1.8g/ml and 44% HCI? CORRECT SIGNIFICANT FIGURES 3. How would we make 1.00L of the solutions below from a stock solution of H₂PO4 with an assay of 66.0% and a density of 1.64: 1.00M, 1.00N, 3.00M, 3.00N CORRECT SIGNIFICANT FIGURES

It was found that 25 ml of a sodium hydroxide solution, which perliter contains 4 g of commercial caustic soda, is equivalent to 12 ml of0.2N sufuric acid. Calculate the percentage of impurities in commercial caustic soda. Note that the molecular weight of NaOH is equat to 40 g/mole.

Calculate % purity and % yeild.  15mL Tert-Butyl (density= 0.78g/mL)  37mL HCl (density=1.18g/mL) 30mL Sodium Bicarbonate  Weight of bottle= 11.21g Weight of final product= 2.275g

Please don't provide handwritten solution ....

In the distillation of the mixture of acetic acid (MW=60.05 g/mole; d=1.05g/ml) and water (MW= 18.00 g/mole; 1.00 g/ml), a total of 0.028 Liters of  1.0 M std NaOH was used to reach the endpoint of a 23 ml of distillate. What is the mole ratio of the CH3COOH  in the mixture? final answer in 3 decimal places.

Calculate the final molarity of H2O2H2O2 if 1.3 mL1.3 mL of the 3.0% w/w H2O23.0% w/w H2O2 solution is diluted with 3.7 mL3.7 mL water, then added to 5.0 mL5.0 mL of a starch-iodide solution.