Standard normal table (page 2) POSITIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 02 .03 .04 .05 .06 .07 .08 09 0.0 .5000 5040 5080 5120 5160 5199 .5239 5279 .5319 .5359 0.1 5398 5438 5478 5517 5557 5596 5636 5675 5714 5753 0.2 5793 5832 5871 5910 5948 5987 .6026 .6064 .6103 .6141 0.3 6179 6217 6255 6293 6331 6368 .64 .6443 6480 .6517 0.4 .6554 6591 6628 6664 .6700 .6736 .6772 .6808 6844 .6879 0.5 .6915 6950 6985 7019 7054 .7088 .7123 7157 7190 .7224 0.6 .7257 7291 7324 7357 7389 7422 7454 7486 7517 7549 0,7 7580 7611 7642 7673 .7704 .7734 7764 7794 7823 .7852 0.8 .7881 7910 7939 7967 7995 8023 8051 8078 8106 .8133 0.9 8159 8186 8212 8238 8264 8289 8315 8340 .8365 8389 1.0 8413 8438 8461 8485 8508 8531 .8554 8577 .8599 8621 1.1 8643 8665 8686 8708 8729 8749 8770 8790 .8810 8830 1.2 8849 8869 8888 8907 8925 8944 8962 .8980 8997 .9015 1.3 9032 9049 9066 .9082 .9099 9115 .9131 .9147 .9162 9177 1.4 9192 9207 9222 9236 .9251 9265 .9279 9292 9306 .9319 1.5 9332 9345 9357 9370 .9382 9394 .9406 9418 9429 9441 1,6 9452 9463 9474 9484 9495 9505 .9515 9525 9535 9545 1.7 9554 9564 9573 .9582 .9591 A 9599 .9608 .9616 .9625 .9633 1,8 9641 9649 .9656 9664 .9671 .9678 .9686 9693 9699 9706 1,9 9713 9719 9726 .9732 9738 .9744 9750 .9756 .9761 9767 2.0 9772 9778 9783 9788 9793 9798 .9803 .9808 .9812 .9817 Print Done

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Find the area under the standard normal distribution curve between z=0 and z=−1.71. Attatched is the distribution table I am using. Thank you for your help!

Suppose a geyser has a mean time between eruptions of 80 minutes. If the interval of time between the eruptions is normally distributed with standard deviation 18 minutes, answer the following questions. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2), (a) What is the probability that a randomly selected time interval between eruptions is longer than 89 minutes? The probability that a randomly selected time interval is longer than 89 minutes is approximately . (Round to four decimal places as needed.) Standard Normal Distribution Table (page 1) Area Standard Normal Distribution 0,03 0.00 0.01 0.02 0.04 0.05 0.06 0.07 0.08 0.09 -34 ー33 0.0003 0.0005 0.0007 0.0003 0.0005 0.0007 0.0003 0.0005 0.0006 0.0003 0.0004 0.0006 0.0003 0.0004 0.0006 0.0003 0.0004 0.0006 0.0003 0.0004 0.0005 0.0003 0.0003 0.0004 0.0005 0.0007 0.0010 0.0002 0.0003 0.0005 0.0007 0.0010 0.0004 0.0006 -32 2 -31 -30 0.0010 0.0013…

Test the hypothesis using the P-value approach. Be sure to verify the requirements of the test Ho: p=0.5 versus H₁: p > 0.5 n = 250; x = 145; a = 0.1 Click here to view page 1 of the table Click here to view page 2 of the table Calculate the test statistic, Zo Zo (Round to two decimal places as needed.) = DE COOK

Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the probability that a randomly selected thermometer reads between -1.71 and -0.31 and draw a sketch of the region. Click to view page 1 of the table. Click to view page 2 of the table. Standard Normal Table (Page 1) Sketch the region. Choose the correct graph below. OA. -1.71 -0.31 The probability is (Round to four decimal places as needed.) OB. NEGATIVE Z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 02 .03 .04 .05 .06 .07 .08 .09 -1.71 -0.31 -3.50 and lower .0001 -3.4 0003 0003 -3.3 .0005 .0005 .0003 .0005 .0003 .0004 .0003 0004 .0003 .0003 .0003 .0003 .0002 .0004 .0004 .0004 .0004 .0003 -3.2 .0007 .0007 .0006 .0006 .0006 .0006 .0006 .0005 .0005 .0005 -3.1 .0010 .0009 .0009 .0009 .0008 .0008 .0008 .0008 .0007 .0007 -3.0 .0013 0013 .0013 0012 0012 .0011 .com .0011 0010 0010 -2.9 .0019 .0018 0018 .0017 0016 .0016 0015 .0015 0014…

Find the value of Z Tables of areas under the normal curve 20,22 Click the icon to view a table of areas under the normal curve. TABLE V 20,22 (Round to two decimal places as needed.) Standard Normal Distribution 02 00 01 03 04 05 06 Arse 0.0003 0.0004 0.0005 0.0002 0.0005 0.0005 0.0007 0.0010 0.0003 0.0003 0.0003 0.0005 0.0005 00005 0.0007 0.0010 0.0009 00009 00009 0.0013 00013 00013 0.0012 0.0003 0.0004 0.0004 0.0004 0.0006 0.0006G 00006 00005 0.0003 0.0004 0.0003 -34 -13 -3.2 -3.1 -1.0 00003 0.0003 0.0004 0.0006 0000 0.0007 0.0008 0.0008 0008 0008 0.0011 0.0007 0.0010 0.0012 0.0011 0001 -29 -28 -27 0.0019 0.00188 0.0018 0017 0.0016 0.0016 00015 00015 E2000 000 0.0023 0.0014 00014 0.0020 00019 0.0026 0.0027 0.0026 0.0025 0.0022 0.0021 G.0021 00035 00034 0033 00032 00031 0.0030 0.0029 0.0028 00047 0.0045 0.0044 0.0043 00041 0040 0.0039 0.008 0.0055 0037 0.0036 -26 -25 0.0049 0.0062 0.0060 0.0059 0.0057 0.0048 0.0066 00064 0.0087 0.0113 0011o 0.0150 0.0146 00143 0.0188 0.0183 -24 -23…

STANDARD NORMAL DISTRIBUTION: Table Values Represent AREA to the LEFT of the Z score. Z .00 .01 .04 .05 .06 .07 .08 .09 .02 .03 .00004 .00004 00004 00004 .00003 .00003 -3.9 .00005 00005 -3.8 00007 .00007 .00007 .00006 .00006 .00005 .00004 .00004 00006 .00006 .00005 .00005 00008 .00012 .00012 .00011 -3.7 .00011 .00010 .00010 .00008 -3.6 .00016 .00015 .00015 .00010 .00009 .00009 00008 .00008 .00014 00014 .00013 .00013 .00020 .00019 .00029 .00028 00023 .00022 .00022 00021 .00019 00018 00017 .00017 -3.5 -3.4 .00034 .00032 .00031 .00030 .00027 .00026 .00025 -3.3 .00048 .00047 .00045 .00043 .00042 .00040 00039 .00038 .00036 -3.2 .00069 .00066 .00064 .00062 .00060 .00058 .00056 .00054 .00052 -3.1 .00097 ,00094 .00090 00084 .00082 .00079 .00076 .00074 -3.0 .00135 .00131 .00126 00118 ,00114 00111 .00107 .00104 -2.9 .00187 .00181 .00175 .00164 .00159 00154 .00149 .00144 00199 -2.8 .00256 .00248 .00240 .00226 .00205 -2.7 .00347 .00336 .00326 00307 .00280 .00272 00427 00415 .00379 .00368 -2.6…

A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of 3364 with a mean life of 530 minutes. If the claim is true, in a sample of 75 batteries, what is the probability that the mean battery life would be greater than 533.2 minutes? Round your answer to four decimal places. Answer How to enter your answer (opens in new window) Tables Keypa Keyboard Shortc

A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the true proportion is 0.06. If 305 are sampled, what is the probability that the sample proportion will be less than 0.08? Round your answer to four decimal places. Answer How to enter your answer (opens in new window) Tables E Keyboa