Standard deviation: 35(0.397) (1 – 0.397) = 2.8946 P(x = 14) = (35) (0.397)¹4 (0.603) 35-14 = (35) (0.397)¹4 (0.603) ²¹ = X - √np(1 − p) P (x17) = 0.8165 P (x > 11) = 0.7947 = P(11 ≤ x ≤ 16) = 0.6972 0.1365 You really struggle remembering to bring your lunch to work. Each day seems to be independent as to whether you remember to bring your lunch or not. The chance that you forget your lunch each day is 39.7%. Consider the next 35 days. Let X be the number of days that you forget your lunch out of the 35 days. Calculate the following: μx: ox: P(X= 14):

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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Hello, I understand most of this problem, but I am stuck understanding how we get 0.603. I underlined it in the images attached below. 

Two images: one of the problem and on of the answer P(X=14). the 0.603 in this answer is where I am stuck on how we get 0.603

 

Thank you!

Standard deviation:
35(0.397) (1 – 0.397) = 2.8946
P(x = 14) = (35) (0.397)¹4 (0.603) 35-14 = (35) (0.397)¹4 (0.603) ²¹
=
X
-
√np(1 − p)
P (x17) = 0.8165
P (x > 11) = 0.7947
=
P(11 ≤ x ≤ 16) = 0.6972
0.1365
Transcribed Image Text:Standard deviation: 35(0.397) (1 – 0.397) = 2.8946 P(x = 14) = (35) (0.397)¹4 (0.603) 35-14 = (35) (0.397)¹4 (0.603) ²¹ = X - √np(1 − p) P (x17) = 0.8165 P (x > 11) = 0.7947 = P(11 ≤ x ≤ 16) = 0.6972 0.1365
You really struggle remembering to bring your lunch to work. Each day seems to be independent as to
whether you remember to bring your lunch or not. The chance that you forget your lunch each day is
39.7%.
Consider the next 35 days. Let X be the number of days that you forget your lunch out of the 35 days.
Calculate the following:
μx:
ox:
P(X= 14):
Transcribed Image Text:You really struggle remembering to bring your lunch to work. Each day seems to be independent as to whether you remember to bring your lunch or not. The chance that you forget your lunch each day is 39.7%. Consider the next 35 days. Let X be the number of days that you forget your lunch out of the 35 days. Calculate the following: μx: ox: P(X= 14):
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