Standard deviation: 35(0.397) (1 – 0.397) = 2.8946 P(x = 14) = (35) (0.397)¹4 (0.603) 35-14 = (35) (0.397)¹4 (0.603) ²¹ = X - √np(1 − p) P (x17) = 0.8165 P (x > 11) = 0.7947 = P(11 ≤ x ≤ 16) = 0.6972 0.1365 You really struggle remembering to bring your lunch to work. Each day seems to be independent as to whether you remember to bring your lunch or not. The chance that you forget your lunch each day is 39.7%. Consider the next 35 days. Let X be the number of days that you forget your lunch out of the 35 days. Calculate the following: μx: ox: P(X= 14):
Standard deviation: 35(0.397) (1 – 0.397) = 2.8946 P(x = 14) = (35) (0.397)¹4 (0.603) 35-14 = (35) (0.397)¹4 (0.603) ²¹ = X - √np(1 − p) P (x17) = 0.8165 P (x > 11) = 0.7947 = P(11 ≤ x ≤ 16) = 0.6972 0.1365 You really struggle remembering to bring your lunch to work. Each day seems to be independent as to whether you remember to bring your lunch or not. The chance that you forget your lunch each day is 39.7%. Consider the next 35 days. Let X be the number of days that you forget your lunch out of the 35 days. Calculate the following: μx: ox: P(X= 14):
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Hello, I understand most of this problem, but I am stuck understanding how we get 0.603. I underlined it in the images attached below.
Two images: one of the problem and on of the answer P(X=14). the 0.603 in this answer is where I am stuck on how we get 0.603
Thank you!
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