St DH+ (4) (+) (37₁) = 0 1+ck) (st S+2 S+3 S (5+3) CS+5) +K (5+2) SCS+3) CS+5) = 0 3) S (5+3) CS+5) +K (3+2) = 0 how to simplify 1 to 2) and 2) to 3)

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A: solution is given below

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A:

Q: 8.1

A: We will solve the problem.

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A:

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A: SOLUTION-

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A: We can solve this as follows:

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A: As per bartleby guidelines we only give first question answers.