SQL: Dog Data In each question below, you will define a new table based on the following tables. CREATE TABLE parents AS SELECT "abraham" AS parent, "barack" AS child UNION SELECT "abraham" , "clinton" UNION SELECT "delano" , "herbert" UNION SELECT "fillmore" , "abraham" UNION SELECT "fillmore" , "delano" UNION SELECT "fillmore" , "grover" UNION SELECT "eisenhower" , "fillmore"; CREATE TABLE dogs AS SELECT "abraham" AS name, "long" AS fur, 26 AS height UNION SELECT "barack" , "short" , 52 UNION SELECT "clinton" , "long" , 47 UNION SELECT "delano" , "long" , 46 UNION SELECT "eisenhower" , "short" , 35 UNION SELECT "fillmore" , "curly" , 32 UNION SELECT "grover" , "short" , 28 UNION SELECT "herbert" , "curly" , 31; CREATE TABLE sizes AS SELECT "toy" AS size, 24 AS min, 28 AS max UNION SELECT "mini" , 28 , 35 UNION SELECT "medium" , 35 , 45 UNION SELECT "standard" , 45 , 60; Q2: By Parent Height Create a table by_parent_height that has a column of the names of all dogs that have a parent, ordered by the height of the parent from tallest parent to shortest parent. -- All dogs with parents ordered by decreasing height of their parent CREATE TABLE by_parent_height AS SELECT "REPLACE THIS LINE WITH YOUR SOLUTION"; For example, fillmore has a parent (eisenhower) with height 35, and so should appear before grover who has a parent (fillmore) with height 32. The names of dogs with parents of the same height should appear together in any order. For example, barack and clinton should both appear at the end, but either one can come before the other. sqlite> select * from by_parent_height; herbert fillmore abraham delano grover barack clinton
SQL
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SQL:
Dog Data
In each question below, you will define a new table based on the following tables.
CREATE TABLE parents AS
SELECT "abraham" AS parent, "barack" AS child UNION
SELECT "abraham" , "clinton" UNION
SELECT "delano" , "herbert" UNION
SELECT "fillmore" , "abraham" UNION
SELECT "fillmore" , "delano" UNION
SELECT "fillmore" , "grover" UNION
SELECT "eisenhower" , "fillmore";
CREATE TABLE dogs AS
SELECT "abraham" AS name, "long" AS fur, 26 AS height UNION
SELECT "barack" , "short" , 52 UNION
SELECT "clinton" , "long" , 47 UNION
SELECT "delano" , "long" , 46 UNION
SELECT "eisenhower" , "short" , 35 UNION
SELECT "fillmore" , "curly" , 32 UNION
SELECT "grover" , "short" , 28 UNION
SELECT "herbert" , "curly" , 31;
CREATE TABLE sizes AS
SELECT "toy" AS size, 24 AS min, 28 AS max UNION
SELECT "mini" , 28 , 35 UNION
SELECT "medium" , 35 , 45 UNION
SELECT "standard" , 45 , 60;
Create a table by_parent_height that has a column of the names of all dogs that have a parent,
ordered by the height of the parent from tallest parent to shortest parent.
-- All dogs with parents ordered by decreasing height of their parent
CREATE TABLE by_parent_height AS
SELECT "REPLACE THIS LINE WITH YOUR SOLUTION";
For example, fillmore has a parent (eisenhower) with height 35, and so should appear before
grover who has a parent (fillmore) with height 32. The names of dogs with parents of the same
height should appear together in any order. For example, barack and clinton should both appear at
the end, but either one can come before the other.
sqlite> select * from by_parent_height;
herbert
fillmore
abraham
delano
grover
barack
clinton
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