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- In a test cross, peas of an unknown genotype are crossed with peas of a known genotype. In this example, smooth peas are the unknown and wrinkled peas are the known (rr). If half of the offspring from that cross are smooth and half are wrinkled, what is the genotype of the unknown plant? O a. Homozygous dominant: RR O b. Homozygous recessive: rr Oc. Incomplete dominance d. Heterozygous dominant: Rr CLEAR MY CHOICERed-green color blindness is an X-linked recessive trait in humans. Two people with color vision have a color-blind son. What are the genotypes of the parents? a. X N X N and X n Yb. X n X n and X n Yc. X N X N and X N Yd. X N X n and X N Ye. X N X n and X n YIn pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross between a pea plant with wrinkled peas (genotype rr) and a plant of unknown genotype that has round peas. Result: 4 plants with round peas. What is the unknown parent? Use Punnett square on homework to help answer the question. O a. Homozygous dominant O b. Heterozygous O c. Homozygous recessive O d.
- In certain species of flies, eye color is controlled by sim-·ple dominance by a single pair of alleles. A red-eyed fly was crossed with a white-eyed fly, both of whose parents had white eyes. All of their offspring (both female and male) had red eyes.a. Which is dominant, the allele for red eyesor the allele for white eyes?b. What is the genotype of the white-eyed parents?c. If the white-eyed parent was mated with one of the red-eyed offspring, what phenotypic ratio wouldyou expect regarding eye color?Perform the following crosses: A. If having a widow's peak is dominant to having a straight hair line. What percentage of the offspring of a heterozygote with a homozygous recessive will have a widow's peak? B. Using what you have learned, predict the phenotypes of the offspring in this cross. G = grey g= brown L = long hair A GGLL mates with a ggll. 1 = short hairIn pea plants, the allele for round seeds (R) is dominant and the allele for wrinkled seeds (r) is recessive. Under what conditions would we observe wrinkled seeds in a pea plant?A. When the plant has a genotype RRB. When the plant inherits a dominant allele from both parentsC. When the plant inherits a recessive allele from both parentsD. When a plant has a heterozygous allelic pair of the gene for seed shape
- If a mouse has a dominant phenotype (P_), how would you determine if it is homozygous (PP) or heterozygous (Pp)? Select one: O a. O b. O c. O d. O e. cross it to a mouse with the dominant trait but a similarly unknown genotype. cross it to a mouse with the recessive trait. cross it to a homozygous dominant mouse. it cannot be determined. cross it to a heterozygous dominant mouse. OIn guinea pigs, black hair (B) is dominant to brown hair (b) and short hair (H) is dominant to long hair (h). A black, long-haired male guinea pig (Bbhh) is crossed with a brown, short-haired female guinea pig (bbHh). 1. What is the genotype of the male parent? 2. What is the phenotype of the female parent? 3. What is the genotype of their baby guinea pig (in the empty box)? (male) Bbhh Bh Bh bh bh bH BbHh Bbhh Bbhh Bbhh (female) bh Bbhh Bbhh Bbhh Bbhh bbHh bH BbHh BbHh bbHh bbHh bh Bbhh bbhh bbhh B= Black hair H= long hair h= short hain b= brown hair BhbH - calico long fur - gray wavy fur a b bhbh - brown short hair - BbHh BbHh - black long hair - black short hair O d Bbhh - brown, short-hair- Bbhh O O 0 0In humans, having freckled skin (F) is dominant. Assume that a homozygous recessive man and a heterozygous woman have a child. a. What is the woman's phenotype? b. Show the Punnett square for the cross. С. What is the child's probability of having no freckles? Uunt
- A male fruit fly is homozygous dominant for gray-body color (G) and is crossed with a female fruit fly that is homozygous recessive for ebony-body color (g). What are the probable phenotypes of the offspring? O A 25% gray, 75% ebony O B. 50% gray, 50% ebony O C. 100% gray O D. 100% ebonySuppose a woman who is a carrier (XNXN)marries a man who is colorblind (XnY). Is there any chance that they will have a male child with a normal color vision? What are the possible phenotypes? 大 A. No chance, 2 female carrier and 2 males colorblind B. Yes, 1 female carrier, 1 female color blind, 1 male with normal color vision and 1 male colorblind C. Yes, 1 female colorblind and 2 males with normal vision and 1 male colorblind D. Yes, 2 males with normal color vision and 2 females carrierIn humans, there are three alleles for blood type: A, B, and O. A and B are codominant over O. A male with type AB blood and a female with type A blood have a child. The male’s parents both had type AB blood. The female’s mother had type A blood and her father had type B blood. What is the potential phenotype of the child? A. type A (25%), type B (25%), type AB (25%), type O (25%) B. type A (25%), type B (50%), type AB (25%) C. type A (25%), type B (25%), type AB (50%) D. type A (50%), type B (25%), type AB (25%)