Sphere m1 with a mass of 1.0 kg collides with m2, which also has a mass of 1.0 kg, in an elastic collision.  If v2f= 15 m/s and θ2= 40°, determine v1i.  (Hint:  An elastic collision requires that the after-collision angle between the two velocities must be 90°.)

A block with mass M = 5.60 kg is sliding in the positive x-direction at Vi = 8.00 m/s on a frictionless surface when it collides elastically in one dimension with a stationary block with mass m = 1.30 kg. Determine the velocities, Vf and vf, of the objects after the collision. Vf = ? vf = ?

The drawing shows a collision between two small balls. Ball (1) has a mass of 140 g and is moving along the x-axis with a velocity of 4.60 m/s. It makes a collision with ball (2), which has a mass of 210 g and is initially at rest. After the 60°). What is the magnitude of %D collision, the two balls fly apart with angles as shown in the figure below (a = 58° and B the velocity of ball (2) after the collision? m/s +y m2 m1 +x

A bullet of mass 0.018 kg traveling horizontally at a high speed of 200 m/s embeds itself in a block of mass 4 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? Vf = 7 X m/s (b) Calculate the total translational kinetic energy before and after the collision. Ktrans,/ = 180 X J Ktrans,f = 260 X J (c) Compare the two results and explain why there is a difference. O The Energy Principle isn't valid for an inelastic collision. The internal energy of the block-bullet system has increased. O Some of the momentum is lost in an inelastic collision.