Spaceships A and B move in opposite directions at the same speed of 0.378c relative to earth, with A moving away from earth and B moving toward earth. Find the velocity of B relative to A. с

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### Understanding Relative Velocity in Opposite Directions

#### Problem Statement:
Spaceships A and B move in opposite directions at the same speed of \( 0.378c \) relative to Earth, with A moving away from Earth and B moving towards Earth. Find the velocity of B relative to A.

#### Solution:
To solve this problem, we can use the concept of relative velocity from the theory of special relativity. In special relativity, the addition of velocities is given by the formula:

\[ v_{rel} = \frac{v + u}{1 + \frac{vu}{c^2}} \]

Where:
- \( v_{rel} \) is the relative velocity of one object with respect to the other.
- \( v \) and \( u \) are the velocities of the two objects relative to the Earth.
- \( c \) is the speed of light.

Given:
- \( v = 0.378c \) (velocity of spaceship A relative to Earth)
- \( u = -0.378c \) (velocity of spaceship B relative to Earth, negative because it moves in the opposite direction)

By substituting these values into the formula, we get:

\[ v_{rel} = \frac{0.378c + (-0.378c)}{1 + \frac{(0.378c)(-0.378c)}{c^2}} \]

Since the velocities are equal but opposite:

\[ v_{rel} = \frac{0.378c + 0.378c}{1 - \left(\frac{0.378^2}{c^2}\right)} \]

Simplifying further:

\[ v_{rel} = \frac{0.756c}{1 - 0.142884} \]
\[ v_{rel} = \frac{0.756c}{0.857116} \]

Finally:

\[ v_{rel} \approx 0.882c \]

So, the velocity of spaceship B relative to spaceship A is approximately \( 0.882c \).

#### Diagram:
*No diagram is provided, but the problem can be visualized with two spaceships moving in opposite directions and Earth as a reference point at the center.*

### Conclusion:
By using the relativistic velocity addition formula, we have determined that the velocity of spaceship B relative to spaceship A is approximately \( 0.882c \). This example demonstrates how special relativity
Transcribed Image Text:### Understanding Relative Velocity in Opposite Directions #### Problem Statement: Spaceships A and B move in opposite directions at the same speed of \( 0.378c \) relative to Earth, with A moving away from Earth and B moving towards Earth. Find the velocity of B relative to A. #### Solution: To solve this problem, we can use the concept of relative velocity from the theory of special relativity. In special relativity, the addition of velocities is given by the formula: \[ v_{rel} = \frac{v + u}{1 + \frac{vu}{c^2}} \] Where: - \( v_{rel} \) is the relative velocity of one object with respect to the other. - \( v \) and \( u \) are the velocities of the two objects relative to the Earth. - \( c \) is the speed of light. Given: - \( v = 0.378c \) (velocity of spaceship A relative to Earth) - \( u = -0.378c \) (velocity of spaceship B relative to Earth, negative because it moves in the opposite direction) By substituting these values into the formula, we get: \[ v_{rel} = \frac{0.378c + (-0.378c)}{1 + \frac{(0.378c)(-0.378c)}{c^2}} \] Since the velocities are equal but opposite: \[ v_{rel} = \frac{0.378c + 0.378c}{1 - \left(\frac{0.378^2}{c^2}\right)} \] Simplifying further: \[ v_{rel} = \frac{0.756c}{1 - 0.142884} \] \[ v_{rel} = \frac{0.756c}{0.857116} \] Finally: \[ v_{rel} \approx 0.882c \] So, the velocity of spaceship B relative to spaceship A is approximately \( 0.882c \). #### Diagram: *No diagram is provided, but the problem can be visualized with two spaceships moving in opposite directions and Earth as a reference point at the center.* ### Conclusion: By using the relativistic velocity addition formula, we have determined that the velocity of spaceship B relative to spaceship A is approximately \( 0.882c \). This example demonstrates how special relativity
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