(b) The formula for the elasto-plastic tangent is on the formula sheet [{fo }{f.o) [De [Dep] = [De] | [1] [1-[88]] {f.o}T [De] {fo } we have [De] from part (a) so the students just need to calculate the derivative of the yield function with respect to stress, {f} {f}={10-1}. Looking at different components of [Dep] (all in GPa) 1 0 -1 270 135 135 135 0 - 135
(b) The formula for the elasto-plastic tangent is on the formula sheet [{fo }{f.o) [De [Dep] = [De] | [1] [1-[88]] {f.o}T [De] {fo } we have [De] from part (a) so the students just need to calculate the derivative of the yield function with respect to stress, {f} {f}={10-1}. Looking at different components of [Dep] (all in GPa) 1 0 -1 270 135 135 135 0 - 135
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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can someone explain how we get to this answer
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hi thank you for your reply when you have put the matrix 135 0 -135,000,-135 0 135 why are the top left and bottom right corner 135 and not 270 ?
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sorry also why have you put 1/270 x the matric i dont see that in the formula ?
how is the final result obtained 202.5 135 202.5 etc
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