Some researchers are doing a two-mean pooled t-test. They have two samples with sizes n1=17 and n2=21. The population standard deviations are unknown but assumed to be equal, so the sample standard deviations are found and used to calculate a pooled standard deviation, sp.For sample 1: s1=9.8 and x¯1=30For sample 2: s2=10.5 and x¯2=27What are the test statistic (t) and the degrees of freedom to perform this test?Select the correct answer below: If sp=10.195, then t=17−21(10.195) 130+127√≈−1.48df=38 If sp=10.195, then t=30−27(10.195) 117+121√≈0.9df=36 If sp=10.195, then t=17−21(10.195) 130+127√≈−1.48df=36 If sp=10.195, then t=30−27(10.195) 130+127√≈1.11df=38 If sp=10.195, then t=17−21(10.195) 117+121√≈−1.2df=36 If sp=10.195, then t=30−27(10.195) 117+121√≈0.9df=38

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Description: Some researchers are doing a two-mean pooled t-test. They have two samples with sizes n1=17 and n2=21. The population standard deviations are unknown but assumed to be equal, so the sample standard deviations are found and used to calculate a pooled

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Some researchers are doing a two-mean pooled t-test. They have two samples with sizes n1=17 and n2=21. The population standard deviations are unknown but assumed to be equal, so the sample standard deviations are found and used to calculate a pooled standard deviation, sp.

For sample 1: s1=9.8 and x¯1=30
For sample 2: s2=10.5 and x¯2=27

What are the test statistic (t) and the degrees of freedom to perform this test?

Select the correct answer below:

If sp=10.195, then t=17−21(10.195) 130+127√≈−1.48

df=38

If sp=10.195, then t=30−27(10.195) 117+121√≈0.9

df=36

If sp=10.195, then t=17−21(10.195) 130+127√≈−1.48

df=36

If sp=10.195, then t=30−27(10.195) 130+127√≈1.11

df=38

If sp=10.195, then t=17−21(10.195) 117+121√≈−1.2

df=36

If sp=10.195, then t=30−27(10.195) 117+121√≈0.9

df=38

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