Solve, using separation of variables, Uxx + Uyy u(x, y) = 1 u(x, y) = 2 = 0 in {(x, y) = R² : 1 < x² + y² < 4}, on {(x, y) Є R² : x² + y² = 1}, on {(x, y) = R²x² + y² = 4}.
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- What are the coordinates of P(23t/2)? А. (-1, 0) В. (1, 0) С. (0,1) D.(0,-1)Find the relationship between x and y such that the point (x,y) is equidistance from the points (7,1) and (3,5)Solve for x: xy2 + yz2 - 4 = 2x - 1. 3-yz2 b) х %3D у2-2 a) x = *y^tyz2-3 2 с) х %3D 3 — yz2 -у? +2 у2-2 d) х— 3-уz?
- The coordinates of the points O, A and B of the plane are (0, 0), (0, 12) and (108, 0), respectively. A point P=(x,y) is such that the area of triangle ΔPOA is twice the area of triangle ΔPOB. We can then say that the coordinates of P satisfy the relationship: Choose an option: a. x^(2)−81/4y^(2)=0 b. x^(2)−324y^(2)=0 c. x^(2)−81y^(2)=0 d. x^(2)−18y^(2)=0 e.x^(2)−54y^(2)=0(у-3) -dy -бу+1 у2