solve the recurrence relation subject to the initial conditions.  Find a closed-form solution for the Lucas sequence L(1) = 1, L(2) = 3, and L(n) = L(n−1)+L(n−2) for n ≥ 3

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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solve the recurrence relation subject to the initial conditions. 

Find a closed-form solution for the Lucas sequence L(1) = 1, L(2) = 3, and L(n) = L(n−1)+L(n−2)
for n ≥ 3.

Expert Solution
Step 1

Given recurrence relation Ln=Ln-1+Ln-2 with initial conditions L1=1 , L2=3 for n3.

This can be written as Ln-Ln-1-Ln-2=0.

Characteristic equations is given by

x2-x-1=0

Solve for x.

x=1±1+42   =1±52x=1+52 or x=1-52

Solution of the recurrence relation is given by

Ln=a1+52n+b1-52n

 

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