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Solve the LP problem in example 3 using Big-M method. Complete the table and find the optimum solution. P = 8x5 – 8x6 + 0S1 – MA1 + OS2 Subject to: x3 – X4 – X5 + X6 – S1 + A1 = 0 2x3 – 2x4 + 3x5 – 3x6 + S2 = 6 Maximize: | X3, X4, X5, X6, S1, A1, S2 > 0 Table 1 Pj 8 -8 -M Prod Qty x3 x4 x5 x6 S1 A1 S2 Zj Pj-Z) Table 2 Pj -8 -M Prod Qty x3 x4 x5 хб S1 A1 S2 Zj Pj-Zj Table 3 Pj -8 -M Prod Qty x3 х4 x5 x6 S1 A1 S2 Zj Pj-Zj Optimal Solution:

Solve the LP problem in example 3 using Big-M method. Complete the table and find the optimum solution. P = 8x5 – 8x6 + 0S1 – MA1 + OS2 Subject to: x3 – X4 – X5 + X6 – S1 + A1 = 0 2x3 – 2x4 + 3x5 – 3x6 + S2 = 6 Maximize: | X3, X4, X5, X6, S1, A1, S2 > 0 Table 1 Pj 8 -8 -M Prod Qty x3 x4 x5 x6 S1 A1 S2 Zj Pj-Z) Table 2 Pj -8 -M Prod Qty x3 x4 x5 хб S1 A1 S2 Zj Pj-Zj Table 3 Pj -8 -M Prod Qty x3 х4 x5 x6 S1 A1 S2 Zj Pj-Zj Optimal Solution:

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter8: Polynomials
Section8.1: Adding And Subtracting Polynomials
Problem 58PPS
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Solve the LP problem in example 3 using Big-M method. Complete the table and find the optimum solution. Maximize: P = 8x5 – 8x6 + 0S1 – MA1 + 0S2 X3 - X4 – X5 +x6 – S1 + A1 = 0 2x3 – 2x4 + 3x5 – 3x6 + S2 = 6 Subject to: X3, X4, X5, X6, S1, A1, S2 > 0 Table 1 Pj 8 -8 -M Prod Qty x3 x4 x5 x6 s1 A1 S2 Zj Pj-Zj Table 2 Pj 8 -8 -M Prod Qty x3 x4 x5 x6 s1 A1 S2 Zj Pj-Zj Table 3 Pj 8 -8 -M Prod Qty x3 x4 x5 x6 s1 A1 S2 Zj Pj-Zj Optimal Solution:
Transcribed Image Text:Solve the LP problem in example 3 using Big-M method. Complete the table and find the optimum solution. Maximize: P = 8x5 – 8x6 + 0S1 – MA1 + 0S2 X3 - X4 – X5 +x6 – S1 + A1 = 0 2x3 – 2x4 + 3x5 – 3x6 + S2 = 6 Subject to: X3, X4, X5, X6, S1, A1, S2 > 0 Table 1 Pj 8 -8 -M Prod Qty x3 x4 x5 x6 s1 A1 S2 Zj Pj-Zj Table 2 Pj 8 -8 -M Prod Qty x3 x4 x5 x6 s1 A1 S2 Zj Pj-Zj Table 3 Pj 8 -8 -M Prod Qty x3 x4 x5 x6 s1 A1 S2 Zj Pj-Zj Optimal Solution:
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