Solve the initial value problem yy' + ¤ = /x² + y² with y(2) = v21. a. To solve this, we should use the substitution help (formulas) u' = help (formulas) Enter derivatives using prime notation (e.g.. you would enter y' for ). b. After the substitution from the previous part, we obtain the following linear differential equation in x, u, u'. help (equations) c. The solution to the original initial value problem is described by the following equation in r, y. help (equations)

Suppose you want to find an equation for a curve that passes through the point (1, 2x3 y 2) and whose slope at any point (x, y) is A. B. C. You'd solve the differential equation Solving this differential equation with the initial condition, you get: E. 2y2 = x4 +7 نيا v2 = 2x4+2 ² = x4 +3 Op. ²x4+4 = D. 1²=14+3 p2 dx -2x³ = with initial condition y(1) = 2.