Solve the following system of nonlinear equation using Newton's Method. (you can use MS Excel) f₁(x) = 0.5x₁ + x₂ +0.5x3 x6 = 0 X7 f₂(x)= x3 + x4 + 2x5 0 f3(x) = x₁ + x₂ + x5 X7 f(x) = -28837x₁ - 139009x2 - 78213x3 + 18927x4 +8427x5 + 2 X7 1 = 0 fs(x) = x₁ + x₂ + x3 + x4 + x5-1=0 f(x) = 400x₁x3-1.7837x105x3x5 = 0 f(x)= x₁x3 - 2.6058x4 = 0 13492 x7 10690 X6 X7
Solve the following system of nonlinear equation using Newton's Method. (you can use MS Excel) f₁(x) = 0.5x₁ + x₂ +0.5x3 x6 = 0 X7 f₂(x)= x3 + x4 + 2x5 0 f3(x) = x₁ + x₂ + x5 X7 f(x) = -28837x₁ - 139009x2 - 78213x3 + 18927x4 +8427x5 + 2 X7 1 = 0 fs(x) = x₁ + x₂ + x3 + x4 + x5-1=0 f(x) = 400x₁x3-1.7837x105x3x5 = 0 f(x)= x₁x3 - 2.6058x4 = 0 13492 x7 10690 X6 X7
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 12CR
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![2. Solve the following system of nonlinear equation using Newton's Method. (you can use MS Excel)
x6
f₁(x) = 0.5x₁ + x₂ +0.5x3- = 0
f₂(x) = x3 + x4 + 2x5
f3(x) = x₁ + x₂ + x5
f4(x) = -28837x₁ - 139009x2 - 78213x3 + 18927x4 +8427x5
+
2
-1=0
X7
1
-1=0
fs(x) = x₁ + x₂ + x3 + x4 + x5-1=0
400x₁x2-1.7837x105x3x5 = 0
f(x) =
f(x) = x₁x3 - 2.6058x4 = 0
13492
x7
106906 = 0
x7](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb544788d-f949-4588-909a-c743bb8cd0d3%2Ff623366e-e148-4d52-a608-6cf94804ad3f%2F6bx3xds_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. Solve the following system of nonlinear equation using Newton's Method. (you can use MS Excel)
x6
f₁(x) = 0.5x₁ + x₂ +0.5x3- = 0
f₂(x) = x3 + x4 + 2x5
f3(x) = x₁ + x₂ + x5
f4(x) = -28837x₁ - 139009x2 - 78213x3 + 18927x4 +8427x5
+
2
-1=0
X7
1
-1=0
fs(x) = x₁ + x₂ + x3 + x4 + x5-1=0
400x₁x2-1.7837x105x3x5 = 0
f(x) =
f(x) = x₁x3 - 2.6058x4 = 0
13492
x7
106906 = 0
x7
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