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Solve the following second order equations: (a) (b) (c) d²y 2 x² + ( )² – ( ² ) ² = 0; y(1) = 2; y'(1) = −1 dx2 dx d²y dy करवर y dx 2 +x x = ln(x); y(1) = 1; y'(1) = d² + (²x) dx2 dx - = dy ; y(0) = 1; y'(0) = 2

Solve the following second order equations: (a) (b) (c) d²y 2 x² + ( )² – ( ² ) ² = 0; y(1) = 2; y'(1) = −1 dx2 dx d²y dy करवर y dx 2 +x x = ln(x); y(1) = 1; y'(1) = d² + (²x) dx2 dx - = dy ; y(0) = 1; y'(0) = 2

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 15CR
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Plz answer part c only
Solve the following second order equations: (a) (b) (c) x d²y + dx² dy ( 22 ) ² − ( ² ) ² = dx 2d²y dx² = 0; y(1) = 2; y'(1) = -1 +xdyy + x dx = In(x); y(1) = 1; y'(1) = 0 y²y + x)² - ; y(0) = 1; y'(0) – 2 у = dy dx = dx² dx
Transcribed Image Text:Solve the following second order equations: (a) (b) (c) x d²y + dx² dy ( 22 ) ² − ( ² ) ² = dx 2d²y dx² = 0; y(1) = 2; y'(1) = -1 +xdyy + x dx = In(x); y(1) = 1; y'(1) = 0 y²y + x)² - ; y(0) = 1; y'(0) – 2 у = dy dx = dx² dx
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