Solve the following ODE, y' + 2y = x+4, y(0) = 1 using. a. Approximate y (0.4) second order Runge-Kutta with h=0.2 and y(0)=0. b. Using the previous results use Adam-Bashforth(predictor) two step explicit method in conjunction with Adam-Moulton two step implicit method (corrector) to approximate y (0.8) with h=0.01 c. Use MATLAB to approximate and plot the solution from x=0 to x=1 using 2nd order Runge-Kutta with h=0.2 and y (0) =1
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- Boolean function is represented by its truth table as follows: хуz f(x,y,z) 000 1 001 1 010 011 100 101 1 110 111 1 (a) Write corresponding minterm expansion. (b) Write corresponding maxterm expansion. (c) Minimize (Simplify) and Represent f(x,y,z) using Karnaugh map (K-map). (d) Minimize (Simplify) f(x,y,z) using Boolean identities. (e) Represent the simplified function using logic diagram.Solved this questionuse the Quine-McCluskey method for the following. Please make sure you show step by step solutions and original work.
- How to solve kmap of boolean expression of truth table of table listed in the image belowUse approximation by integrals to show the tight bounds (Big-Theta)of the following summations. Note: you must plot the diagrams to assist your proof. Sigma i = 1 to n (i)Simplify the expression using Quine-McCluskey Method. M(U,V,W,X,Y,Z) = Em(5, 13, 21, 23, 29, 31, 37, 39, 45, 53, 61)
- Given the following Boolean Function: F(w,x,y,z) = Σ(8,10,12,14) Show the function in the truth table in column F. 1. 2. 3. 4. 5. 6. Determine the minterms, and create the SOP expression. Determine the maxterms, and create the POS expression. Create the Karnaugh map (K-Map) for the Function, complete the groupings, and determine the minimized expression. Draw the logic diagram for the K-Map minimized expression. Verify the K-map expression is equivalent to the original function using the truth table provided (showing all the steps to reach the outcome).Simplify the following Boolean functions, using Karnaugh maps: a. F(w, x, y, z) = E(0,2,3,8,10,11) b. F(A, B,C, D) = E(1,5,9,12,13,15) %3DI need the answer as soon as possible
- Simplify the following Boolean functions by using Karnaugh map method. (a) F1(A, B,C, D) = Em(0,1,4, 5, 8, 9, 10, 12, 13) (b) F2(A, B,C, D) = Em(3,5, 7, 8, 9, 10, 11, 13, 15) %3DA Boolean function F (A,B,C) of truth table at below(PLS step by step) 1,Provide the minterm expansion of F . 2,Provide the minterm expansion and the maxterm expansion of F’s complement, respectively. Assume that we don’t care the value of F when ABC=001. i. What is the minterm expansion of F? ii. Choose a proper value for the don’t care term and provide the shortest possible expression of POS (product of sum) for F . (Hint: Minimize the number of maxterms)Using Karnaugh Maps, simplify the following Boolean Expression: T = ABC + AC + AB + ABC +ĀCD + ABD given that B cannot be 1 if C is 0.