Solve the following initial value problem for r as a function of t. d²r Differential equation: =4e'i-3ej+9e3tk dt² Initial conditions: r(0) = 6i+j+3k dr = -i+5j dt t=0 Find the general antiderivative. OA. r(t) = (4e' + cx1+x2)i+ (-3e-cy₁t+cy2)j + (e³ +11+ C₂2) K OB. r(t)=4e'i-3e j + 3e³tk+C t+c c. (t) = (4² +x+6x)+(-3¹ + cy₁1+2)+(++)k OD. r(t)=4eli+3e¯j+3e3tk+C Solve the initial value problem for r as a vector function of t. r(t)=i+i+k

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