HW6 Q18 Solve the following initial value problem for r as a function of t.d²rDifferential equation:=4e'i - 3e¹j+9e3tkdt2Initial conditions:r(0) = 6i+j+3kdr= -i+5jdtIt=0Find the general antiderivative.OA. r(t)=) = (4e² + cx₁t + Cx2) i + (-3e¹ - Cy₁t+C2) j + (e³t + Cz₁t+C₂2) kOB. r(t)=4e¹i-3ej + 3e³k+Cc. (t) = (4e² + cx1+x)+(-3¯ + cy₁l+2)+(e³ + + 2) kOD. r(t)=4e¹i+3e¯j+3e3k+CSolve the initial value problem for r as a vector function of t.r(t)=i+j+kPart 2 of 2Po

Given Differential equation is as follows

Solve the following initial value problem for r as a function of t. d²r Differential equation: =4e'i-3ej+9e3tk dt² Initial conditions: r(0) = 6i+j+3k dr = -i+5j dt t=0 Find the general antiderivative. OA. r(t) = (4e' + cx1+x2)i+ (-3e-cy₁t+cy2)j + (e³ +11+ C₂2) K OB. r(t)=4e'i-3e j + 3e³tk+C t+c c. (t) = (4² +x+6x)+(-3¹ + cy₁1+2)+(++)k OD. r(t)=4eli+3e¯j+3e3tk+C Solve the initial value problem for r as a vector function of t. r(t)=i+i+k

Solve the following initial value problem for r as a function of t. d²r Differential equation: =4e'i-3ej+9e3tk dt² Initial conditions: r(0) = 6i+j+3k dr = -i+5j dt t=0 Find the general antiderivative. OA. r(t) = (4e' + cx1+x2)i+ (-3e-cy₁t+cy2)j + (e³ +11+ C₂2) K OB. r(t)=4e'i-3e j + 3e³tk+C t+c c. (t) = (4² +x+6x)+(-3¹ + cy₁1+2)+(++)k OD. r(t)=4eli+3e¯j+3e3tk+C Solve the initial value problem for r as a vector function of t. r(t)=i+i+k

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter14: Discrete Dynamical Systems

Section14.3: Determining Stability

Problem 13E: Repeat the instruction of Exercise 11 for the function. f(x)=x3+x For part d, use i. a1=0.1 ii...

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