Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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Solve (image) using two integral techniques (must be different) and when done factor them both and combined like a terms. Make sure you show that they initially look different however are actually the same.
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- Please help solvearrow_forwardFind all solutions for the indicated variable in the following equations. Follow any other directions for each indicated part. (a) 2x^2-3x-5=0; solve for x by using the factoring method. (b) 3/n-2/n^2=1; Solve for n.arrow_forwardThis is our quadratic equation: 5x^2 - 10x - 45 = -5 Use the completing the square method to answers the following questions. 1.You do not need to do step one for this particular quadratic.. Single choice. true false 2.After doing (or not doing) step 1, your equation looks like which one? Single choice. x^2 - 2x - 9 = -1 5x^2 - 10x - 45 = -5 3.After doing step 2, the equation looks like which one? . Single choice. x^2 - 2x = 10 x^2 - 2x + 9 = -1 x^2 - 2x = 8 x^2 - 2x - 9 = -1 4.After doing step 3 the equation looks like which one? Single choice. x^2 - 2x = 8 x^2 - 2x + 1 = 9 x^2 - 2x + 10 = 8 x^2 - 2x + 1 = 10 5.After doing step 4, the equation looks like which one? Single choice. (x - 3)(x + 3) = 8 (x - 1)^2 = 9 (x + 1)(x - 1) = 8 (x + 3)^2 = 9 6.A radical cancels. Single choice. a logarithm division the second power 7.When you take the square root of a number you always get. Single choice. a positive or…arrow_forward
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