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Solve for: VB = V  VE = V  IE =  mA  VCE = V  VC = V  re' = ohms

Solve for: VB = V  VE = V  IE =  mA  VCE = V  VC = V  re' = ohms

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question 12:

USE APPROXIMATE ANALYSIS
USE 2 decimal places, no commas.

Given: 
Single-stage, voltage-divider biased, common-emitter with

  1. VCC = 15V
  2. R1 = 46kohms               
  3. R2 = 7kohms
  4. RC = 4kohms
  5. RE = 1kohms
  6. RS = 6ohms
  7. RL = 1kohms
  8. βDC = βAC = 141

C1 andC2 are coupling capacitors.

C3 is bypass capacitor


Solve for:

  1. VB = V 
  2. VE = V 
  3. IE =  mA 
  4. VCE = V 
  5. VC = V 
  6. re' = ohms 
  7. Rin(base) = kohms 
  8. Rin(tot) = kohms 
  9. Voltage gain (Av) = 
  10. Attenuation (Att) = 
  11. Overall voltage gain (AVT) = 
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