Solve for the values of x₁, x₂ and x3using: 0.30x₁ +0.52x₂ + 1.50x3 = -0.01 0.50x₁ + 1.25x2 +0.25x3 = 0.67 x₁ +0.30x₂ +0.50x3 = -0.44 Using: a. Jacobi Iteration. Use & = 0.1%

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Solve for the values of x₁, x₂ and x3using:
0.30x₁ +0.52x2 +1.50x3 = -0.01
0.50x₁ + 1.25x₂ +0.25x3 = 0.67
x₁ + 0.30x₂ +0.50x3 = -0.44
Using:
a. Jacobi Iteration. Use &
=
0.1%
Transcribed Image Text:Solve for the values of x₁, x₂ and x3using: 0.30x₁ +0.52x2 +1.50x3 = -0.01 0.50x₁ + 1.25x₂ +0.25x3 = 0.67 x₁ + 0.30x₂ +0.50x3 = -0.44 Using: a. Jacobi Iteration. Use & = 0.1%
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