SOLVE FOR THE SHEAR AND MOMENT DIAGRAM: USE ONLY AREA METHOD. SHOW COMPLETE SOLUTION FOR DETERMINATION OF THE SHEAR AND MOMENT VALUES, THE CORRECT BEHAVIOR OF THE GRAPH, DEGREE OF CURVE, RATIO AND PROPORTION FOR ZERO SHEAR, AND MAXIMUM MOMENT WITH RESPECT TO THE ZERO SHEAR. Pe Ws Im Im Im 2m 2m 4m 2m Im

SOLVE FOR THE SHEAR AND MOMENT DIAGRAM: USE ONLY AREA METHOD. SHOW COMPLETE SOLUTION FOR DETERMINATION OF THE SHEAR AND MOMENT VALUES, THE CORRECT BEHAVIOR OF THE GRAPH, DEGREE OF CURVE, RATIO AND PROPORTION FOR ZERO SHEAR, AND MAXIMUM MOMENT WITH RESPECT TO THE ZERO SHEAR. Pe Ws Im Im Im 2m 2m 4m 2m Im

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Draw and label the diagram correctlyShow the complete solution. Determine the following:a. Shear and Bending Moment Equationb. Shear and Bending Moment Diagramc. Mmax
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=3.5 ft, b=9.0 ft, c=4.0 ft, d=3.5 ft, w = 5.5 kips/ft and P = 45 kips. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. For this loading, calculate the reaction forces Ay and Ey acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) Ay =___________ kips, Ey = __________ kips. Determine the shear force acting at each of the following locations:(a) x = 0+ ft (i.e., just to the right of support A)(b) x = 3.5 ft(c) x = 12.5 ft(d) x = 16.5– ft (i.e., just to the left of D)(e) x = 16.5+ ft (i.e., just to the right of D)(f) x = 20.0– ft (i.e., just to the left of support E) Answer: a to f ) V = ________ kips Use the graphical…
Im doing a shear and moment calculation for a problem graphically and keep getting a negative sign in my moment calculation where I should be getting a postive sign. I know that the integral of my shear calculation is going to be my moment equation but I always use this to "check" myself against my work after I do my standard summation of moments about a point. I KNOW I SHOULD be getting M_2(x) = -.5x^2 + 2x + c but as you can see by my work I keep getting a "-2x". Why is this and where am I going wrong?
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=3 ft, b=9 ft, c=3 ft and w=3 kips/ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. a a * Answers: Ay = Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) B t b P W b W C- C₂ с kips, Cy= p D -X kips.
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=4.0 ft, b-9.0 ft. c=4.0 ft, d=3.0ft, w=8 kips/ft and P = 66 kips. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. B B ÎÎÎÎÎÎ Answers: Ay=i b d For this loading, calculate the reaction forces Ay and Ey acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) W C b C C D E kips, Ey = i E X Ey kips.
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=4.0 ft, b-8.0 ft, c-4.0 ft, d=3.0 ft, w = 6.5 kips/ft and P = 45 kips. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. A a a B Part 2 b d For this loading, calculate the reaction forces Ay and Ey acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) Save for Later B W Answers: Ay = i 37.575 eTextbook and Media W AV=P₂ b C V₁ - V₁ = Sw(x) dx C C с D + D d kips, Ey= M₂ E i E ZA x Ey X Incorrect If your answer for part (a) or (e) is incorrect, recall that concentrated loads create discontinuities in the shear-force diagram. Refer to the table below (Construction Rules for Shear-Force and Bending-Moment Diagrams), Rule 1. At…
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=3 ft, b-9 ft, c=2 ft and w=10.5 kips/ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. B Ay B b Answers: Ay = i Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) W b CS W C₁ Cy с D kips, Cy= i kips.
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=4.0 ft, b=8.0 ft, c=4.0 ft, d=3.0 ft, w = 6.5 kips/ft and P = 45 kips. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. A A a B a B W Answers: Ay = i b d For this loading, calculate the reaction forces Ay and Ey acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) W с b C C P C D P kips, Ey = d E i E X 'y x kips.
Use the graphical method to construct the bending-moment diagram and identify the magnitude of the largest moment (consider both positive and negative). The ground reactions and the shear-force diagram are provided. M = 14 kN-m Ay = 3.54 KN Dy = 32.46 kN Units: KN Ay M 4m O 31.52 kN-m O 20.0 kN-m O 33.6 kN-m 23.2 kN-m O 26.1 kN-m B Ay 4 m 15 kN C A, 4 m A,-15 7 kN/m D 3 m 21 A₁-15 E X
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=4.0 ft, b=8.0 ft, c=4.0 ft, d=3.0 ft, w = 6.5 kips/ft and P = 45 kips. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. A a B a b For this loading, calculate the reaction forces Ay and Ey acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) W B W ÎÎÎÎÎÎ b C C d E d E X Ey X
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=4.0 ft, b=8.0 ft, c=4.0 ft, d=3.0 ft, w = 6.5 kips/ft and P = 45 kips. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. a B a W B W C b d For this loading, calculate the reaction forces Ay and Ey acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) b C C P C D P Ľ E d E ·x Ey
Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Leta = 5.2 ft, w = 235 Ib/ft, Mp = 7000 lb-ft, and P = 11001b. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. Mp Determine the bending moment acting at each of the following locations: (a) x = 5.2 ft (i.e., at point B) (b) x = 10.4 ft (i.e., at point C) (c) x = 15.6 – ft (i.e., just to the left of point D) (d) x = 15.6 + ft (i.e., just to the right of point D) (e) x = 20.8 ft (i.e., at point E) When entering your answers, use the bending moment sign convention.