Solve for the resultant of the two vectors in kN. *

1 ft 3 ft B 3 ft 3 ft (-9002 + 800f + 1000k) Ib.ft 6 ft 3 ft E (-300î – 400ĵ + 100k) Ibs The applied force at point E and the applied couple moment at point D are shown in the figure. Complete/calculate the following: (Where applicable, express the results as the (x, y, z) components of a Cartesian vector) 1. Draw the free-body diagram (FBD), showing the appropriate reaction forces and/or moments at the supports. (You must show the reactions in their component form i.e. show RAx, MRAX etc. on the FBD). Note: The support at point A is not able to resist a moment about the 'X' axis but is able to resist a force in this direction. 2. ME, which is the moment vector at point A due to the force acting at point E 3. Me, which is the moment vector at point A due to the tension force acting at point B. Write the vector in terms of the unknown tension magnitude 'T' 4. Set up the equations of equilibrium (You must show all relevant equilibrium equations one below the other. 5. Calculate the…

Problem 5 For the following figure, ● Find the reactions expressed as x and y force components Find the reactions expressed as a vector with magnitude and direction ● F = 650 N 100 45° F₂ = 750 N F = 900 N