Structural Analysis
Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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Textbook: Strength of Materials

 

Please provide step by step solution.

 

A formula sheet is provided for your reference.

The cross section of a beam is shown below. The formula for the Moment of Inertia about the x-axis at the centroid of the section is shown below. Outer Diameter = 50 mm Inner Diameter = 40 mm Ixc = (douter - dinner) dinmer) 64 a) Solve for the moment of inertia, about the x-axis at the centroid. b) Using the parallel axis theorem, solve for the moment of inertia, about the x-axis at the top of the shape.
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Transcribed Image Text:The cross section of a beam is shown below. The formula for the Moment of Inertia about the x-axis at the centroid of the section is shown below. Outer Diameter = 50 mm Inner Diameter = 40 mm Ixc = (douter - dinner) dinmer) 64 a) Solve for the moment of inertia, about the x-axis at the centroid. b) Using the parallel axis theorem, solve for the moment of inertia, about the x-axis at the top of the shape.
Formula Sheet Centre of Gravity and Moment of Inertia ΣΑ ΣΑ EA, ΣΑ I, = I, + Ad² I¸ =E(!.)+ E(Ad²) 1, = E(!.)+ y Axial Stress and Internal Forces ΣΕ, -0 Σ , =0 ΣΜ=0 o = P/ A T =V | A S.F. = o alow /o. allow actual Strain PL 8 = AE · E \ateral V = E = E = L E axial
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Transcribed Image Text:Formula Sheet Centre of Gravity and Moment of Inertia ΣΑ ΣΑ EA, ΣΑ I, = I, + Ad² I¸ =E(!.)+ E(Ad²) 1, = E(!.)+ y Axial Stress and Internal Forces ΣΕ, -0 Σ , =0 ΣΜ=0 o = P/ A T =V | A S.F. = o alow /o. allow actual Strain PL 8 = AE · E \ateral V = E = E = L E axial
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