Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN: 9781337614085
Author: Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher: Cengage,
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**Problem:**

Solve for the lengths of the missing sides in the triangle. Leave your answer in radical form. Show your work and explain the steps you used to solve.

**Diagram Explanation:**

The diagram depicts a right triangle with the following details:
- One angle is 30°.
- The other angle is 60°.
- The side opposite the 60° angle (hypotenuse) is labeled as 18.
- The side opposite the 30° angle is labeled as \( b \).
- The side adjacent to the 30° angle (and opposite to the 60° angle) is labeled as \( a \).

**Solution:**

In a 30°-60°-90° triangle, the ratios of the sides are 1 (shortest side): \(\sqrt{3}\) (longest side): 2 (hypotenuse).

1. **Find Side \( a \):**
   Since the hypotenuse \( c \) is 18, side \( a \) (the longer leg) is \(\frac{\sqrt{3}}{2} \times c\).
   
   \[
   a = \frac{\sqrt{3}}{2} \times 18 = 9\sqrt{3}
   \]

2. **Find Side \( b \):**
   Since \( b \) (the shorter leg) is half of the hypotenuse:

   \[
   b = \frac{1}{2} \times 18 = 9
   \]

**Final Answer:**

- \( a = 9\sqrt{3} \)
- \( b = 9 \)

The values have been left in radical form as requested.
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Transcribed Image Text:**Problem:** Solve for the lengths of the missing sides in the triangle. Leave your answer in radical form. Show your work and explain the steps you used to solve. **Diagram Explanation:** The diagram depicts a right triangle with the following details: - One angle is 30°. - The other angle is 60°. - The side opposite the 60° angle (hypotenuse) is labeled as 18. - The side opposite the 30° angle is labeled as \( b \). - The side adjacent to the 30° angle (and opposite to the 60° angle) is labeled as \( a \). **Solution:** In a 30°-60°-90° triangle, the ratios of the sides are 1 (shortest side): \(\sqrt{3}\) (longest side): 2 (hypotenuse). 1. **Find Side \( a \):** Since the hypotenuse \( c \) is 18, side \( a \) (the longer leg) is \(\frac{\sqrt{3}}{2} \times c\). \[ a = \frac{\sqrt{3}}{2} \times 18 = 9\sqrt{3} \] 2. **Find Side \( b \):** Since \( b \) (the shorter leg) is half of the hypotenuse: \[ b = \frac{1}{2} \times 18 = 9 \] **Final Answer:** - \( a = 9\sqrt{3} \) - \( b = 9 \) The values have been left in radical form as requested.
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