Solve each problem. See Examples 1 and 2. 19. Distance Flown by a Plane A plane flies 1.3 hr at 110 mph on a bearing of 38°. It then turns and flies 1.5 hr at the same speed on a bearing of 128°. How far is the plane from its starting point? 128° 38 52 30 a-1.3x 10= 143 bol.5x110= 105 L DBC = 180-120=52 LABD= 38° a2+bz=CZ LABC=52+30=90° 1143 + 16524 C=V 1432+1652 C=218.3 1.5 hs

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Hi,

Im stuck in one of the problems in my trig. book and i think i need help in the entire problem bc i dont know where my mistake is.

attached is a picture of the textbook question, but ill write it here as well.

19. Distance flown by a Plane. A plane flies 1.3 hr at 110 mph on a bearing of 38°. It then turns and flies 1.5hr at the same speed on a bearing of 128°. How far is the plane from its starting point?

Ill also attach a picture of what I worked on but im sure its wrong. I checked in the back of the book and the answer should be 220 mi but i have no idea how they got that answer.

please help!!

thank you!

Solve each problem. See Examples 1 and 2.
19. Distance Flown by a Plane A plane flies 1.3 hr
at 110 mph on a bearing of 38°. It then turns and
flies 1.5 hr at the same speed on a bearing of 128°.
How far is the plane from its starting point?
128°
38
Transcribed Image Text:Solve each problem. See Examples 1 and 2. 19. Distance Flown by a Plane A plane flies 1.3 hr at 110 mph on a bearing of 38°. It then turns and flies 1.5 hr at the same speed on a bearing of 128°. How far is the plane from its starting point? 128° 38
52
30
a-1.3x 10= 143
bol.5x110= 105
L DBC = 180-120=52
LABD= 38°
a2+bz=CZ
LABC=52+30=90°
1143 + 16524
C=V 1432+1652
C=218.3
1.5 hs
Transcribed Image Text:52 30 a-1.3x 10= 143 bol.5x110= 105 L DBC = 180-120=52 LABD= 38° a2+bz=CZ LABC=52+30=90° 1143 + 16524 C=V 1432+1652 C=218.3 1.5 hs
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