Solve: 25. 3

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Solve:
= 25.
We will use a property of equality to isolate the variable on one side of the
equation.
To solve the original equation, we want to find a simpler equivalent equation of the
form x = a number, whose solution is obvious.
To isolate x, we use the multiplication property of equality. We can undo the division by 3 by multiplying both sides by 3.
25
This is the equation to solve.
3
Multiply both sides by 3.
= 3
3x
= 75
Do the multiplications.
Simplify
3x
by removing the common factor of 3 in the numerator and denominator:
= 1.
1x =
X =
The coefficient 1 need not be written since 1x = x.
If we substitute 75 for x in
25, we obtain the true statement 25 = 25. This verifies that 75 is the solution. The solution set is {75}.
Solve:
b
= 2.
28
b =
m/3
Transcribed Image Text:Solve: = 25. We will use a property of equality to isolate the variable on one side of the equation. To solve the original equation, we want to find a simpler equivalent equation of the form x = a number, whose solution is obvious. To isolate x, we use the multiplication property of equality. We can undo the division by 3 by multiplying both sides by 3. 25 This is the equation to solve. 3 Multiply both sides by 3. = 3 3x = 75 Do the multiplications. Simplify 3x by removing the common factor of 3 in the numerator and denominator: = 1. 1x = X = The coefficient 1 need not be written since 1x = x. If we substitute 75 for x in 25, we obtain the true statement 25 = 25. This verifies that 75 is the solution. The solution set is {75}. Solve: b = 2. 28 b = m/3
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