Sodium reacts violently with water according to the equation: 2 Na(s) + 2 H2O(l) → 2 NaOH(aq) + H2(g) The resulting solution has a higher temperature than the water prior to the addition of sodium. What are the signs of AH° and AS° for this reaction? C) AH° is positive and AS is negative. A) AH° is negative and AS° is negative. OB) AH° is negative and AS° is positive. D) AH° is positive and AS° is positive.

In the following acid-base equilibria of weak acids in water, label the acid (A), the base (B), the conjugate acid (CA), and the conjugate base (CB). HCIO,(aq) + H,O(l) = H,O*(aq) + ClO, (aq) ******* H₂CO3(aq) + H₂O(1) = H₂O+ (aq) + HCO3(aq) H₂O(1) + CH3NH3(aq) → CH3NH₂(aq) + H₂O+ (aq) O $0 CH3COOH(aq) + H₂O(1) ⇒ CH₂COO¯(aq) + H₂O+ (aq) Answer Bank CA CB

For the following equilibrium reaction: NaOH(Aq) + HCl(aq) HOH(aq) + NaCl(aq) + Δ What happens if you add: A) KCl B)KBr

Suppose you add a few drops of ammonia into a bucket of water. Then you add a couple of drops of phenolphthalein into the bucket. The color of the water becomes pink or red. Now you have a weird idea. If you spray that colored water on to the white clothes of your friends, they will be very annoyed. What will be the color of the clothes after a few minutes? Explain.

Part A Water ionizes by the equation =H+(aq) + OH (ag) The extent of the reaction is small in pure water and dilute aqueous solutions. This reaction creates the following relationship between [H*] and [OH ]: What is the H† concentration for an aqueous solution with pOH = 2.73 at 25 °C? Express your answer to two significant figures and include the appropriate units. Kw = [H*][OH¯] • View Available Hint(s) Keep in mind that, like all equilibrium constants, the value of Kw changes with temperature. ? [H*] = Value Units

Acetaldehyde (CH3CHO) is an important chemical both industrially and biologically.  For instance, it is a (somewhat toxic) intermediate in the body's metabolism of ethanol into acetic acid, and thus is possibly implicated in the "hungover" symptoms of someone who has had too much to drink the night before.  In aqueous solution, it establishes an equilibrium with a hydrated form, shown below. CH3CHO (aq)   +   H2O (l)   <-->  CH3CH(OH)2 (aq) You start with an aqueous sample, already at equilibrium, with the CH3CH(OH)2 (the hydrated form) at a concentration of 2.60 M.  You have no information about how much, if any, of the anhydrous form (CH3CHO) is initially in the flask.  If you add 2.0 M of CH3CHO to the reaction flask, and as the equilibrium is being restored the amount of CH3CH(OH)2 changes by 1.13 M, what is the final amount of CH3CHO?

Calculate the pOH of a 9.44 X 10-8 M Mg(OH)2 solution.  I need the work otherwise I wont understand it