So the solution to this problem was supposed to be -3: "Since the slope of the line is 4, we know that the rise over run is 4/1. Therefore, for every increase of 1 in x, there is an increase of 4 in y. Starting from (-3, 5), we can move 2 units to the left and 8 units down to get to the x-axis. Therefore, the y-coordinate of the point where the line intersects the x-axis is 5 – 8 = -3." I don't see how they got -3 and not 0...what am I not understanding? p.s. this is a "hard" GRE quantitative reasoning ques

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter1: Equations And Graphs
Section1.3: Lines
Problem 92E
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So the solution to this problem was supposed to be -3:

"Since the slope of the line is 4, we know that the rise over run is 4/1. Therefore, for every increase of 1 in x, there is an increase of 4 in y. Starting from (-3, 5), we can move 2 units to the left and 8 units down to get to the x-axis. Therefore, the y-coordinate of the point where the line intersects the x-axis is 5 – 8 = -3."

I don't see how they got -3 and not 0...what am I not understanding?

p.s. this is a "hard" GRE quantitative reasoning ques

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Okay that's a much better explanation, however I'm still lost. Why do we need to move "two units to the right along the x-axis" to reach the x-axis?? How did you determine this? I'm having trouble visualizing what you are talking about...

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