Snapchat No Snapchat Total Instagram 34 No Instagram Total 51 2. Suppose that we randomly choose a student from class. Find the following probabilities. P(Instagram) = P(Snapchat) = P(No Instagram) = P(No Snapchat) = P(Instagram AND no Snapchat) = P(Instagram AND Snapchat) = %3D P(No Instagram AND No Snapchat) : P(Snapchat AND No Instagram) =

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Chapter1: Combinatorial Analysis
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1. Complete the table . 2. Find the following probabilities
A school survey of 51 statistics students at BFIT revealed that 46 students are currently using Instagram, and 37
students are using snapchat. A total of 34 students are using both. Complete the two-way frequency table below.
1.
Collect class data to fill in the following two-way table.
Snapchat
No Snapchat
Total
Instagram
34
No Instagram
Total
51
2.
Suppose that we randomly choose a student from class. Find the following probabilities.
P(Instagram) =
P(Snapchat) =
P(No Instagram) =
P(No Snapchat) =
P(Instagram AND no Snapchat) =
P(Instagram AND Snapchat) =
P(No Instagram AND No Snapchat) =
P(Snapchat AND No Instagram) =
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Transcribed Image Text:A school survey of 51 statistics students at BFIT revealed that 46 students are currently using Instagram, and 37 students are using snapchat. A total of 34 students are using both. Complete the two-way frequency table below. 1. Collect class data to fill in the following two-way table. Snapchat No Snapchat Total Instagram 34 No Instagram Total 51 2. Suppose that we randomly choose a student from class. Find the following probabilities. P(Instagram) = P(Snapchat) = P(No Instagram) = P(No Snapchat) = P(Instagram AND no Snapchat) = P(Instagram AND Snapchat) = P(No Instagram AND No Snapchat) = P(Snapchat AND No Instagram) = to add speaker notes MacBook Pro く ** & %3D $ #3 3 7 8. 4 E R T Y G H J K M C V command option ービ .. .- V この つ LO
Expert Solution
Step 1

Solution:

Given information:

Total students = 51

46 students are using Instagram.

37 students are using Snapchat.

and 34 students are using both.

 

 

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