Sketch a SINGLE graph that includes all of the conditions below. • f'(x) > 0 when - 4< x < 1 f'(x) < 0 when x < -4 and when x > 1 - 5 f(-4) f(1) = 5

Q: 4. Graph the function f(x)=x² +1 ²+1 analytically describing its characteristics.

A: The given function is, f(x)=1x3+1. We need to describe the characteristics of the function from it's…

Q: Let f(x)=x^2−8x+5 with domain 0<x<4 Calculate (f^−1)′(−2)

A:

Q: f(x) = |x| · : %3D Then f-l(x) = if x > 0, and f-l (x) = if x < 0.

A:

Q: - For the following graphical representation of a function f(x): (1) Mark the points on the graph…

A: Since you have posted a question with multiple subparts, so we will solve only the first three…

Q: value of x does the function f(x)=x^3-3x^3 attain the absolute maximum in the interval

A: Given, f(x)=x3-3x3=-2x3 Interval = (-1,4)

Q: 13) Graph if f(x) = x when x = -1,2,4, or 8; f'(x) = 0 if x = -1,2,4, or 8; f'(x) 0 throughout…

A: Given: 1. fx=x when x=-1,2,4,8.            2. f'x=0 when x=-1,2,4,8.            3. f'x&lt;0 for…

Q: Let x +1 f(x) = x + 9

A:

Q: sketch a graph with these restrictions. Label any max/min points and any point of inflections

A: Step 1: Step 2: Step 3: Step 4:

Q: The graph of f'(x) is shown in the figure below. This is not the graph of f(x). 1 (a) List the…

A:

Q: Sketch the graph that possesses the characteristics listed below. f'(-7) = 0, f"(- 7) 0, f(- 3) = -…

A:

Q: f(x) 5 1 -1

A:

Q: if f(X)=(1-2X)^5 then find f`(X)

A:

Q: Sketch a possible graph of a function that satisfies all of the following conditions: f'(2) = 0,…

A:

Q: Shown is a graph of y=f(x) Evaluate f^-1(1)

A: Given, y=f(x) Graph

Q: 1. + + -1 1 2 3. a. Use the graph to explain why, for h > 0, f(a – h) – f(a) -h f(a + h) – f(a) <…

A: The formula for f’(x) for f(x) = 2x is given asddxax=axlnaif a=2 then:ddx2x=2xln2f'x=2xln2

Q: Sketch the graph of a function that satisfies all of the given conditions. f'(0) f'(x) > 0 if x 4,…

A:

Q: Ay Use the given graph of y = f(x) to evaluate the following. (a) f(-3) (b) f(2) (c) f(0) (d) f(-3)…

A: