Sketch a possible graph of a function that satisfies the following conditions. (1) F(x) > 0 on (-0,3), F'(x) <0 on (3,00) (4) f(x) > 0 on (-0, -6) and (6, 00), F"(x) <0 on (-6, 6) im(x)=-3, lim f(x)=0 Solution Condition (0) tells us that is increasing on (-00, 3) and decreasing on (3, 0). Condition (1) says that is concave upward on (-0.) and (,0), and concave downward on First we draw the horizontal asymptote y=-3 as a dashed line (see the figure). A From condition (ill) we know that the graph of fhas two horizontal asymptotes: y and yo @ We then draw the graph of f approaching this asymptote at the far left, increasing to its maximum point atx-3 and decreasing toward the axis at the far right. We also make sure that the graph has inflection points when x-6 and. Notice that we made the curve bend upward for x <-6 and x>6, and bend downward when is between and 6.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Sketch a possible graph of a function of that satisfies the following conditions.
(1)
f'(x) > 0 on (-∞0, 3), f'(x) < 0 on (3, 00)
F"(x) > 0 on (-∞, -6) and (6, co), F"(x) < 0 on (-6, 6)
lim f(x) = -3, lim f(x) = 0
Solution
Condition (i) tells us that f is increasing on (-00, 3) and decreasing on (3,00). Condition (ii) says that f is concave upward on -00,
First we draw the horizontal asymptote y = -3 as a dashed line (see the figure).
y
Ar
3
6
,00)..
and concave downward on
From condition (iii) we know that the graph of f has two horizontal asymptotes: y =
Ⓡ
We then draw the graph of f approaching this asymptote at the far left, increasing to its maximum point at x = 3 and decreasing toward the x-axis at the far right. We also make sure that the graph has inflection points when x = -6 and
is between
and 6.
and y = 0.
. Notice that we made the curve bend upward for x < -6 and x > 6, and bend downward when x
Transcribed Image Text:Sketch a possible graph of a function of that satisfies the following conditions. (1) f'(x) > 0 on (-∞0, 3), f'(x) < 0 on (3, 00) F"(x) > 0 on (-∞, -6) and (6, co), F"(x) < 0 on (-6, 6) lim f(x) = -3, lim f(x) = 0 Solution Condition (i) tells us that f is increasing on (-00, 3) and decreasing on (3,00). Condition (ii) says that f is concave upward on -00, First we draw the horizontal asymptote y = -3 as a dashed line (see the figure). y Ar 3 6 ,00).. and concave downward on From condition (iii) we know that the graph of f has two horizontal asymptotes: y = Ⓡ We then draw the graph of f approaching this asymptote at the far left, increasing to its maximum point at x = 3 and decreasing toward the x-axis at the far right. We also make sure that the graph has inflection points when x = -6 and is between and 6. and y = 0. . Notice that we made the curve bend upward for x < -6 and x > 6, and bend downward when x
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