Situation 8: Light grade steel channels are used as purlins as shown in the figure. The top chords ofthe truss are inclined at 1V:4H. The trusses are spaced at 6m on center. The purlins are spaced at 6m on center. The purlins are spaced at 1.20m on centers. The roof are as follows: Dead load including roof materials Live load Wind load 720MPA 1,000MPA 1,440MPA Wind pressure coefficient Windward Leeward 0.20 0.60 Channel properties Section modulus, S. Section modulus, S Weight 6.19x10 mm 1.38x10 mm 79/m The allowable bending stresses are E = 207MPA and E = 207MPA. Assume that all %3D the loads pass through the centroid of the channels. 1.20 1.20 EEÉ Ë È EE agrod

The truss is suppored by a pin in point A and a roller at point F. Show your FBD

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Compute for the force in each member of the truss in figure 1. (show a complete and neat solution)

Prove that the trusses shown are statically determinate and solve for the force members required for each item. Show your complete solution with figures.

Thank you And please kindly write legibly because I'm having a hard time reading, guessing, and understanding the handwriting of different experts recently. Thanks  Please refer to the photo below. Activity: METHOD OF JOINTS

3) Determine the Force in each member of the truss shown in the Figure. (Use the Method of Joints.) D B gl 12' H E 300lb 300lb goolb 9' 9'

ASSIGNMENT #6 CASE 2 Purlin Design The figure shown has trusses 5.5m apart with midpoint sag rods and Purlins spaced 2.5m on center. The roof truss is inclined 1 vertical to 2 horizontal. The weight of roofing materials is 0.8 kPa, wind load is 0.7 kPa perpendicular to the roof surface, minimum roof live load is 0.6 kPa. Design a channel section of steel Fy = 345 mPa, for the purlins. Use LRFD and ASD of NSCP 2015.