Situation 6: The total flow from Reservoir A in the figure is 650 L/s. The rate flow of pipeline 4 is 380 L/s. Neglect minor loss(velocity head of pipeline 4)18. Determine the hedloss at pipeline 419. Determine the headloss at pipeline 220. Compute the rate of flow of pipeline 221. Compute the length of pipeline 122. Compute the elevation of reservoir BVEL 50 mD = 600 mmf = 0.02L-1850 mD-750 mmf = 0.022L = 4600 mD 300 mmmf = 0.0224EL 15 mL= 4500 mD = 500 mmf0.019

Step 1: Step 2: Step 3: Step 4:

Answered: Situation 6: The total flow from…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A 170-m long pipeline, composed of two pipes connected in series, discharges freely at a point 40 m below the water level at intake. The pipe projects into the reservoir. The first 100 m is 25 cm in diameter, and the remaining 70 m is 15 cm in diameter. Assuming that f=0.05 for both pipes, (a) find the rate of flow. If the junction of the two sizes of pipe is 25 m below the intake water-surface level, find the pressure head just above C and just below C, where C denotes the point of junction. Assume a sudden contraction at C. Use k=0.8 for entrance, 0.24 for sudden contraction and 1.0 for exit. I will downvote the incorrect solution
Problem 5: Energy Grade Line (EGL) and Hydraulic Grade Line (HGL) A small pipe discharges into a big pipe as sketched below. The head loss per length for the small pipe is 0.5 ft head per 1.0 ft length, or ho/L=0.5. The head loss in the big pipe is negligible. There is 1.0 ft of head loss associated with the transition from the small pipe to the big pipe. Which of the following sketches most accurately describes the hydraulic grade line (HGL), shown dashed, and the energy grade line (EGL), shown solid? Choose (a)-(d), re- sketch, and explain your choice. (a) (b) (c) (d)
5 (c)
Consider the pipe network shown. Water enters at 440li/sec at node A and goes out at a rate of 110li/sec at node D and at 330li/sec at E. Use a friction factor of 0.02 using Darcy Weishback formula for head loss. Determine the correction factor for the two loops, the corrected flow for the pipelines and show the corrected flow in the diagram. Check the flows at each node. 440li's L=700m A D=100mm E L=900m D=150mm 330li/s D L=900m D=100mm L=1800m D=150mm В For CE: L=600m D=200mm L=400 D=180mm 110li's ANSWER: a) ¤1 = 0.0129, x2 = 0.0763 b) AB = 0.2329, BE = 0.1863, CE = 0.1437 m³/s, %3D DC = 0.0971, BC = 0.0466, AD = 0.2071
pls do not round off the decimal. only in the final answer
2-A water well is fully penetrates a confined aquifer, as shown in the figure, the external radius of the gravel pack around the water well is 35cm. The length of well screen is 25m and the well discharge is 0.15m3/s. Assess the validity of Darcy's law for this flow. Jse p=1000 kg/m³, µ =1.14×10-3 pa.s, d=1mm)
ELEV. = 75m 1 ... A L = 1700m D = 400mm f = 0.02 ELEV. = 15m C D L = 3500m D = 800mm f = 0.03 A three reservoir problem shown in the figure with their corresponding length and diameter. Determine the discharge in all pipes. (A) Q1 = 0.431 m3/s, Q2 = 0.295 m3/s, Q3 = 0.726 m3/s (B) Q1 = 0.327 m3/s, Q2 = 0.458 m3/s, Q3 = 0.785 m3/s Q1 = 0.295 m3/s, Q2 = 0.413 m3/s, Q3 = 0.708 m3/s (D) No answer among the choices E Q1 = 0.346 m3/s, Q2 = 0.402 m3/s, Q3 = 0.748 m3/s (F) Q1 = 0.286 m3/s, Q2 = 0.519 m3/s, Q3 = 0.805 m3/s 2 ELEV. = 40m B L = 1900m D = 500mm f = 0.025 3
Subject : Fluid mechanics Urgenttttttt please... Give me right solution
46. Situation 16 - The flow of water from Reservoir A shown is 600 L/s. Properties of the system are as follows: a. Determine the water surface elevation, in meters, of reservoir B for the flow to be possible. Round off to two decimal places. b. Determine the flow in Line 3 in L/s. Round off to two decimal places. c. Determine the headloss, in meters, in Line 1. Round off to two decimal places.
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