Single slit: a = 0.04 mm, l = 650 nm, l = 90 cm xm = _1.45cm_______(measured) xc = _1.46 cm_____ (calculated) %difference = 0.685 % θd = sin^-1(m λ/a) = sin-1 (1(650*10^-9)/(4*10-5)= 0.93o part 1: a)Validate that it was correct to use the small angle approximation for that activity: b)Describe the diffraction pattern for one-slit experiment: pleae answer part 1 questions a and b

Single slit: a = 0.04 mm, l = 650 nm, l = 90 cm xm = _1.45cm_______(measured) xc = _1.46 cm_____ (calculated) %difference = 0.685 % θd = sin^-1(m λ/a) = sin-1 (1(65010^-9)/(410-5)= 0.93o part 1: a)Validate that it was correct to use the small angle approximation for that activity: b)Describe the diffraction pattern for one-slit experiment: pleae answer part 1 questions a and b

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter27: Wave Optics

Section: Chapter Questions

Problem 48P

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On a certain crystal, a first-order X-ray diffraction maximum is observed at an angle of 27.1° relative to its surface, using an X-ray source of unknown wavelength. Additionally, when illuminated with a different, this time of known wavelength 0.137 nm, a second-order maximum is detected at 37.3°. Determine (a) the spacing between the reflecting planes, and (b) the unknown wavelength.
Problem 18: Consider a single slit that produces its first minimum at 54° for 590 nm light.Randomized Variablesθ1 = 54 °θ2 = 67 °λ1 = 590 nm Part (a) What is the width of the single slit, w, in nanometers?Numeric : A numeric value is expected and not an expression.w = __________________________________________Part (b) Find the wavelength, in nanometers, of light that has its first minimum at 67°.Numeric : A numeric value is expected and not an expression.λ2 = __________________________________________
Problem 18: Consider a single slit that produces its first minimum at 54° for 590 nm light. Randomized Variablesθ1 = 54 °θ1 = 54 °θ2 = 67 °λ1 = 590 nm Part (a) What is the width of the single slit, w, in nanometers?Numeric : A numeric value is expected and not an expression.w = __________________________________________ Part (b) Find the wavelength, in nanometers, of light that has its first minimum at 67°.Numeric : A numeric value is expected and not an expression.λ2 = __________________________________________
The pupil of a cat's eye narrows to a slit of width 0.5 mm in daylight. Assuming a wavelength of 500 mm, what is the angular resolution? (1 nm = = 10 m) a. 10-³ rad (122) 5 x 10 rad (1.22) 10 rad 21.22) 5x 10 rad (1.22) 500 x 10 m 0.5*10-3m Sing = 1.224 Sin² [1222] = 0 0=0.0012 rad -3 1.22 ÷ 1.2 x 10 rad 1.0 x 103 (1.22) ra 10 x 10-4 (1.22) ra
Problem 17: Suppose a 1.8 μm wide slit produces its first minimum for 410 nm violet light.Randomized Variablesλv = 410 nmλv = 410 nmλr = 750 nmw = 1.8 μm Part (a) Calculate the angle at which this occurs for violet light in degrees.Numeric : A numeric value is expected and not an expression.θv = __________________________________________Part (b) Where is the first minimum (in degrees) for 750 nm red light?Numeric : A numeric value is expected and not an expression.θr = __________________________________________
= សៀគ្វីបើកចំហគឺជាធាតុនៃសៀគ្វីដែលមានរេស៊ីស្តង់ធអនេក។ ៥.កុងឌុចតង់ mhos(Q) កុងឌុចតង់ជារង្វាស់ភាពចម្លងនៃសារធាតុមួយ។គេតាងដោយG។វាត្រូវបានវាស់ជា y siemens (S) 1G= ។ចម្រាសនៃរេស៊ីស្ទីវីតេហៅថា កុងឌុចទីវីតេច = = (Sm") ។ 1 1 R លំហាត់ ២.ខ្សែទង់ដែងមួយមានអង្កត់ផ្ចិត1cm និងរេស៊ីស្តង់ 0.15.2 ។គេយកខ្សែនេះទៅ ហូត(ពន្លូត) យ៉ាងណាអោយអង្កត់ផ្ចិតវាថយចុះ50%នៃអង្កត់ផ្ចិតដើម។គណនារេស៊ីស្តង់ថ្មី។ ៣.គណនារស៊ីស្តង់ទង់ដែងមួយមានមាឌ 1m3។ p = 1.6x10) “Qn ក.នៅពេលគេហូតខ្សែនេះអោយមានអង្កត់ផ្ចិត 0.32mm។ ខ.នៅពេលគេដំខ្សែនេះទៅជាបន្ទះរាងការដែលមានកំរាស់1.2mm។ចរន្តឆ្លងពីមុខកាត់មួយមុខ កាត់មួយ។ 4.ខ្សែ Problem 4. Calculate the resistance of a 2 km length of aluminium overhead power cable if the cross-sectional area of the cable is 100 mm². Take the resistivity of aluminium to be 0.03 x 1()6 Km រូបវិទ្យាសំរាប់វិស្វករ Problem 7. Determine the resistance of 1200 m of copper cable having a diameter of 12 mm if the resistivity of copper is 1.7 x 10–8 Km ៦.មេគុណសីតុណ្ហភាពនស៊ីស្តង់ (Temperature Co-efficient of Resistance) ♥ បើ R, , ,…
Problem 17: Suppose a 1.8 μm wide slit produces its first minimum for 410 nm violet light.Randomized Variablesλv = 410 nmλr = 750 nmw = 1.8 μm Part (a) Calculate the angle at which this occurs for violet light in degrees.Numeric : A numeric value is expected and not an expression.θv = __________________________________________Part (b) Where is the first minimum (in degrees) for 750 nm red light?Numeric : A numeric value is expected and not an expression.θr = __________________________________________
Problem 20: Consider 642 nm light falling on a single slit of width 19.5 μm.Randomized Variablesλ = 642 nmw = 19.5 μm Part (a) Find the angle, in degrees, of the third diffraction minimum for the light.Numeric : A numeric value is expected and not an expression.θ3 = __________________________________________Part (b) What slit width (in micrometers) would place this minimum at 85.0°?Numeric : A numeric value is expected and not an expression.w' = __________________________________________
If y(x,)= (8.3mm) sin [kx+ (o00 nd/s)t + @ disabes a wave teaveling along how much tioe does ang ginen polnt on the steing take to move between dispacements. 生一 %3D a steing, = + 2,7mm And =-2. 7 mm ?
Problem 1: In a double slit experiment the first minimum for 415 nm violet light is at an angle of 42°. Randomized Variables 2 = 415 nm e = 42 ° Find the distance between the two slits in micrometers. d= 8 9 5 6 sin() cos() tan() 7 HOME cotan() asin() acos() E A 4 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() END O Degrees O Radians Vol BACKSPACE DEL CLEAR +
a)- Two Waves ohd in tesfesence with each other. The anblitide Ym of Each wv is 8.9mm chnd phote diffeence blw them is go°. chot Phage differne in tadineond wavelmothe, will give Jesullant wave mo ve in 8 dme ste tched staing dise tion abng a on Onoplitude of 3.5mm?
Problem 5: Consider light that has its third minimum at an angle of 24.4° when it falls on a single slit of width 3.55 µm . Randomized Variables e = 24.4 ° w = 3.55 µm Find the wavelength of the light in nanometers. 2 = 789 E AAL 4 |5 | 6 1| 2 sin() cos() tan() HOME cotan() asin() acos() atan() acotan() sinh() 3 cosh() tanh() cotanh() END O Degrees O Radians vol BACKSPACE DEL CLEAR Submit I give up! Hint Feedback