sin(0) = 1. Therefore, for small values of 0, we have that ne x 1. 3° is a fairly small angle, so we sin(0) We saw that lim might want to conclude that sim3) » 1 or equivalently, sin(3°) × 3. Based on the possible values of sine function, discuss that this approximation is inaccurate. Why do you think this is so off?

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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2. We saw that \(\lim_{{\theta \to 0}} \frac{\sin(\theta)}{\theta} = 1\). Therefore, for small values of \(\theta\), we have that \(\frac{\sin(\theta)}{\theta} \approx 1\). \(3^\circ\) is a fairly small angle, so we might want to conclude that \(\frac{\sin(3^\circ)}{3} \approx 1\) or equivalently, \(\sin(3^\circ) \approx 3\). Based on the possible values of sine function, discuss that this approximation is inaccurate. Why do you think this is so off?
Transcribed Image Text:2. We saw that \(\lim_{{\theta \to 0}} \frac{\sin(\theta)}{\theta} = 1\). Therefore, for small values of \(\theta\), we have that \(\frac{\sin(\theta)}{\theta} \approx 1\). \(3^\circ\) is a fairly small angle, so we might want to conclude that \(\frac{\sin(3^\circ)}{3} \approx 1\) or equivalently, \(\sin(3^\circ) \approx 3\). Based on the possible values of sine function, discuss that this approximation is inaccurate. Why do you think this is so off?
Expert Solution
Solution:

We have limθ0sinθθ=1.

Then, sinθθ1

However, sin3°3°1 is inaccurate.

As θ0, sinθθ1 is accurate for very small θ close to zero.

Here, the angle 3° is much away from 0°.

 

 

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