sin z Prove that lim Cosz - = 1 and lim = 0. Z→0 Z Z→0 Z Hint: use the definition of the derivative, f'(0) = lim Z→O ƒ(z) – ƒ (0) Z

Use the definition of derivative, f'(x) = lim Hh)-r, to calculate the derivative of the folllowing function: fx+h)-f ) t h 0 f(x) = 3x- COPYRIC 7 Format Tools Table B A 2 Tv I U

The limit below represents a derivative f'(a). Determine f(x) and а. sin (5 + h) – 1 | lim h-→0 h O f(x) = sin(x + y) f(x) = sin(x + h) O f(x) = sin(x) sin(x) f(x) = f(x) = sin(x) – 1 a = 2 a = -1 a = 0 a = 1 а — 2

can you explain what this means step by step