sin 0 Use the relation lim = 1 to determine the limit. 0→0 4х + 4x сos (4x) lim 5 sin (4x) cos (4x) X→0

2 sin(rx) Va – 1 Find lim

sin2 Evaluate the following Iimit. 5(cosx-1) Im cinx Change the glven Indeterminate form Into a deteminate form. Choose the correct answer below. 5( cotx-1) O A. sin x O B. -5(1+ cos x) C. - (1+ + cos X) sin x OD. 5( cotx-1) Evaluate the limit. Select the correct cholce below and, if necessary, fll in the answer box to complete your cholce. 5( cos x- 1) O A. Im because each function is continuous for all x. (Simplify your answer.) OB. The limit does not exist and is neither oo nor - co.

Lim as x approaches 0 sin(2x)/sin(3x) Im not sure what steps to take after getting to indeterminant form of 0/0