sin? 0 = 1 – cos² 0 -1-() V3 =1 - 25 25 sin 0 = ± 20 sin 0 = The given expression of cosine is positive and tangent function is given to be less than 0, that is, negative, thus 0 must lie in quadrant IV. Now, take the negative value of the square root, because 0 is in quadrant IV and sine function is negative in quadrant IV. The value of sin 0, when cos (–Ø) tan 0 < 0, is – 2v3
sin? 0 = 1 – cos² 0 -1-() V3 =1 - 25 25 sin 0 = ± 20 sin 0 = The given expression of cosine is positive and tangent function is given to be less than 0, that is, negative, thus 0 must lie in quadrant IV. Now, take the negative value of the square root, because 0 is in quadrant IV and sine function is negative in quadrant IV. The value of sin 0, when cos (–Ø) tan 0 < 0, is – 2v3
sin? 0 = 1 – cos² 0 -1-() V3 =1 - 25 25 sin 0 = ± 20 sin 0 = The given expression of cosine is positive and tangent function is given to be less than 0, that is, negative, thus 0 must lie in quadrant IV. Now, take the negative value of the square root, because 0 is in quadrant IV and sine function is negative in quadrant IV. The value of sin 0, when cos (–Ø) tan 0 < 0, is – 2v3
How can you tell if theta lies in a certain quadrant when working with trigonometric identities?
I can solve the problem but I have a hard time knowing where theta lies and the concept behind it.
please help
thank you
Transcribed Image Text:sin? 0 = 1 – cos² 0
-1-()
V3
=1 -
25
25
sin 0 = ±
20
sin 0 =
The given expression of cosine is positive and tangent function is given
to be less than 0, that is, negative, thus 0 must lie in quadrant IV.
Now, take the negative value of the square root, because 0 is in quadrant
IV and sine function is negative in quadrant IV.
The value of sin 0, when cos (–Ø)
tan 0 < 0, is – 2v3
Equations that give the relation between different trigonometric functions and are true for any value of the variable for the domain. There are six trigonometric functions: sine, cosine, tangent, cotangent, secant, and cosecant.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, trigonometry and related others by exploring similar questions and additional content below.
