Simpsons & mule : Śh f(x dx a h = b-a, 2 J-8 S₁ √₁+x³ dx = b f(x) dx = 1/2 [ Yo + y₂ + yon 3 1 (8₁ +85+---+ 2 (1₂+ Y₁+ ---)] Here, So 2 y h The value of table x 1.4142 n = 4 ه نام b = 1.81 b-a 3 1.2 0.8 4 andy 1.6517 1.9349 1.569 1.4 Z f(x)=√√√1+x3 using Simpsons & mule, 3 ( f(x) dx = 0.2 = 0:2 [(1.4142 +2·6138) + 4(1.6577 +2.2574) + 2(1.9349)] √1+x³dx a rounded off to 0.2 1.6 . 2.2574 2[(1.4142 +2.6138) + 4×3.909 + 2x (1.9349)] 1.8 1.579 2.6138 3 decimal places.
Simpsons & mule : Śh f(x dx a h = b-a, 2 J-8 S₁ √₁+x³ dx = b f(x) dx = 1/2 [ Yo + y₂ + yon 3 1 (8₁ +85+---+ 2 (1₂+ Y₁+ ---)] Here, So 2 y h The value of table x 1.4142 n = 4 ه نام b = 1.81 b-a 3 1.2 0.8 4 andy 1.6517 1.9349 1.569 1.4 Z f(x)=√√√1+x3 using Simpsons & mule, 3 ( f(x) dx = 0.2 = 0:2 [(1.4142 +2·6138) + 4(1.6577 +2.2574) + 2(1.9349)] √1+x³dx a rounded off to 0.2 1.6 . 2.2574 2[(1.4142 +2.6138) + 4×3.909 + 2x (1.9349)] 1.8 1.579 2.6138 3 decimal places.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Simpsons & mule :
·b
So
a
Here
1.8
S₁ √₁+x³ dx
h₂ b-a,
2
b
f(x) dx = 1/2 [ Yo + y₂ +
yn
3
2
y
So
)
b-a
4
The value of table x
h
1
1.4142
9
n = 4
•1.8
b = 1.8
1.2
0.2
3
1(8₁+ Y3+ --- +
2 (J₂+ Y₁+ ---)]
using Simpsons & mule,
( f(x) dx
1
.8
4
andy
1.569
1.4
1.6517 1.9349 2.2574
f(x) = √√√√1+x3
[(1.4142 +2·6138) +
rounded off to
0.2
√ 1+x²³ dx 2
1.6
3
4(1.6577 +2.2574) +
2(1.9349)]
3
0.2 [(1.4142 +2.6138) + 4×3.9091
+2.x (1.9349) ]
1.8
2.6138
1.579
decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe4cdec65-7837-40d3-b239-1cf845d9f9e2%2F90448ecf-7376-44a9-8938-c961c908c129%2Fo6nakfs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Simpsons & mule :
·b
So
a
Here
1.8
S₁ √₁+x³ dx
h₂ b-a,
2
b
f(x) dx = 1/2 [ Yo + y₂ +
yn
3
2
y
So
)
b-a
4
The value of table x
h
1
1.4142
9
n = 4
•1.8
b = 1.8
1.2
0.2
3
1(8₁+ Y3+ --- +
2 (J₂+ Y₁+ ---)]
using Simpsons & mule,
( f(x) dx
1
.8
4
andy
1.569
1.4
1.6517 1.9349 2.2574
f(x) = √√√√1+x3
[(1.4142 +2·6138) +
rounded off to
0.2
√ 1+x²³ dx 2
1.6
3
4(1.6577 +2.2574) +
2(1.9349)]
3
0.2 [(1.4142 +2.6138) + 4×3.9091
+2.x (1.9349) ]
1.8
2.6138
1.579
decimal places.
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