simple random sample and it is normal. In a survey of 1002 people, 701 said that they voted in a recent presidential election. a) Find the best point estimate for the population proportion. b) Find the margin of error that corresponds to a 90% confidence level. c) Find the 90% confidence interval estimate of the populati
It is a simple random sample and it is normal.
In a survey of 1002 people, 701 said that they voted in a recent presidential election.
a) Find the best point estimate for the population proportion.
b) Find the margin of error that corresponds to a 90% confidence level.
c) Find the 90% confidence
Here it is given that -
In a survey of 1002 people, 701 said that they voted in a recent presidential election.
Total number of sample (n) = 1002
Sample proportion (p) = = 0.7
a) Here we know that, the sample proportion is the best possible estimate for the population proportion.
So, the best point estimate for the population proportion = = p =
b) the margin of error that corresponds to a 90% confidence level (E) =
= 1.645 *
= 1.645 * 0.014
= 0.023
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